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likoan [24]
3 years ago
12

Please guys I am begging you to help me! This was due yesterday and I need help! SO please help!

Mathematics
1 answer:
jeka57 [31]3 years ago
8 0

Answer:

  • Q3. 12 units
  • Q4. 6.33 units
  • Q5. 66.19°

Step-by-step explanation:

Q3

DE and DF are legs and EF is hypotenuse

  • DE = √EF² - DF²
  • DE = √13² - 5² = √169 - 25 = √ 144 = 12
  • DE = 12 units

Q4

PR is opposite side of angle Q and RQ is adjacent side

  • tan 54 = PR/RQ
  • tan 54 = PR / 4.6
  • PR = 4.6tan 54
  • PR = 6.33 units

Q5

As previous question, using tan as BC is opposite and AC is adjacent leg of angle A

  • tan A = 6.8/3
  • tan A = 2.266
  • A = arctan (2.266)
  • A = 66.19°
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Harrizon [31]

Answer:

(3, 24)

Step-by-step explanation:

5 0
2 years ago
The ratio of green M&Ms to
saveliy_v [14]

Answer:

the ratio is 2 to 5, all M&M's in total 28

Step-by-step explanation:

2 green to 5 yellow.

if there are 28 M&M's

you will count by 2 every 5

2 , 4 , 6 , 8 , 10

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4 0
2 years ago
How many positive integers between 1000 and 9999 inclusive
bekas [8.4K]

Answer:

Step-by-step explanation:

a.

first number is  1000-1+9=1008

9)1000(1

    9

-------

     10

       9

    -----

       10

         9

       ----

         1

       ----

last number is 9999

9| 9999

  ---------

    1111 |0

    --------

9999=1008+(n-1)9

9999-1008=(n-1)9

n-1=8991/9=999

n=999+1=1000

b.

first digit=1000

last digit=9999-1=9998

2 |9999

  ---------

  |4999|1

9998=1000+(n-1)2

(n-1)2=9998-1000=8998

n-1=4499

n=4499=1=5000

c.not sure

d.

total  numbers=9000

9999=1000+(n-1)1

9999-1000=n-1

n=8999+1=9000

numbers divisible by 3=3000

first number=1002

last number=9999

9999=1002+(n-1)3

(n-1)3=9999-1002=8997

n-1=2999

n=2999+1=3000

numbers not divisible by 3=9000-3000=6000

e.

numbers divisible by 5=1800

first number=1000

last number=9995

9995=1000+(n-1)5

(n-1)5=9995-1000=8995

n-1=1799

n=1799+1=1800

numbers divisible by 7=1286

7 | 1000

  ---------

  |  142-6

1000-6+7=1001

7 | 9999

  |---------

    1428-3

9999-3=9996

first digit=1001

last digit=9996

9996=1001+(n-1)7

(n-1)7=9996-1001=8995

n-1=1285

n=1285+1=1286

numbers divisible by 35=257

first digit=1015

35 ) 1000 ( 28

        70

       ----

        300

        280

        ------

           20

           ---

1000-20+35=1015

35)9999(285

     70

    ----

     299

     280

     -----

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last digit=9999-24=9975

9975=1015+(n-1)35

(n-1)35=9975-1015=8960

n-1=8960/35=256

n=257

reqd. numbers=1800+1286-257=3019

7 0
3 years ago
13. Tom has $14 more than you do.
puteri [66]

Answer:

46

Step-by-step explanation:

14-60 equals 46 and just go to your answer and put that in and there u go buddy

8 0
3 years ago
PLZ QUICK!!
iragen [17]

Answer:

See attached graph

Step-by-step explanation:

The equation is y-3=(x + 6)

Write the equation in a slope intercept form, then graph the equation on a graph tool to see the points that line on the line.

Alternatively , using the coordinates in the answer choices given, input them in the equation of the graph and select the answer choice that has all its coordinates true to the equation.

y-3 = x+6  -----can be written as : y= x+9

Graph  y= x+9 to see the graph and the points that are on the line as attached.

3 0
3 years ago
Read 2 more answers
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