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Eduardwww [97]
3 years ago
11

Which expressions are equivalent to 2 Superscript 5 times 2 Superscript 4? Check all that apply.

Mathematics
1 answer:
ratelena [41]3 years ago
3 0

Note: Consider the given figure attached with this question.

Given:

The expression is:

2^5\times 2^4

To find:

The equivalent expression.

Solution:

We have,

2^5\times 2^4

It can be written as:

2^5\times 2^4=2^{5+4}

2^5\times 2^4=2^{9}

So, option A is correct and option B is incorrect.

Similarly, in options C, D, E,

2\cdot 2^9=2^{10}

2^{10}\cdot 2^2=2^{12}

2^{-2}\cdot 2^{11}=2^{9}

So, options C and D are incorrect but option E is correct.

The given expression can be written as:

(2\cdot 2\cdot 2\cdot 2\cdot 2)\cdot (2\cdot 2\cdot 2\cdot 2)

So, option F is correct.

Therefore, the correct options are A, E F.

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The weights of five oranges are 7.47 ounces, 7.23 ounces, 6.46 ounces, 7.48 ounces, and 6.81 ounces. Using the clustering estima
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Using the clustering estimation technique the approximate total weight oranges is 35 ounces.
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3 years ago
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A team t-shirt costs $3 per adult and $2 per child. On a certain day, the total number of adults (a) and children (c) who bought
lesya [120]
A+c=100

3a+2c=275, from the first c=100-a making the 2nd equation become:

3a+2(100-a)=275 perform indicated multiplication on left side

3a+200-2a=275  combine like terms on left side

a+200=275, subtract 200 from both sides

a=75, and since c=100-a

c=100=75=25

So the answer is D.  25 children and 75 adults
                                 Equation 1: a+c=100
                                 Equation 2: 3a+2c=275
8 0
3 years ago
6m-2 = m+13 how do i solve it
kakasveta [241]
First move the terms to get
6m-m=13+2
Then collect the like terms and calculate the sum, 5m=15
Divide both sides by 5
And you get m=3
4 0
3 years ago
Solve for x<br> -5x+3(x+5)=11<br> Simplify your answer as much as possible
Tcecarenko [31]

Answer: x  = 7

Step-by-step explanation:

-5x + 3(x + 5) = 1

-5x + 3x + 15 = 1

-2x + 15 = 1

-2x = -14

x = \frac{-14}{-2}

x = 7

5 0
2 years ago
A company that produces an expensive stereo component is considering offering a warranty on the component. Suppose the populatio
Llana [10]

Answer:

Warranty of 66 months.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 84, \sigma = 9

If the company wants no more than 2% of the components to wear out before they reach the warranty date, what number of months should be used for the warranty?

Only the lowest 2% will be replaced, so the warranty is the value of X when Z has a pvalue of 0.02. So it is X when Z = -2.055.

Z = \frac{X - \mu}{\sigma}

-2.055 = \frac{X - 84}{9}

X - 84 = -2.055*9

X = 65.5

Warranty of 66 months.

5 0
3 years ago
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