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Anna11 [10]
2 years ago
11

Pls help me out with this An exercise club offers three payment plans for aerobics classes. Plan A charges $6 per class plus a o

ne-time membership fee of $35. Plan B charges $5 per class plus a one-time membership fee of $50. Plan C offers unlimited aerobic classes for a one-time membership fee of $149.
Part A: Write and solve an inequality to find how many classes you would have to attend for Plan A to be a better value than Plan B.

Part B: Write and solve an inequality to find how many classes you would have to attend for Plan A to be a better value than Plan C.

Part C: The club reduces the cost of Plan C to $100. If you attend 15 classes, which plan is now the best value?
Mathematics
1 answer:
wlad13 [49]2 years ago
8 0

Answer:

Class A costs $41 per class so to have a greater value than B you have to attend the class 2 times.

Step-by-step explanation:

41*2= $82

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y=31x/15 < y=27x/13 < y=15x/7 < y=13x/6 < y=11x/5 < y=21x/9 (=7x/3) < y=19x/8

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since all equations base on a linear, simple expression of x, we can simply compare the fractions.

in general, the bigger the number at the bottom, the smaller the individual fraction. that is our first indicator.

we then notice that many fractions represent the value of 2 plus one fraction.

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the only exceptions are 21/9 and 19/8

but 21/9 is actually 7/3 = 2 1/3

and fits therefore into the list above.

that leaves 19/8 = 2 3/8.

the list above can be sorted based on the single fraction at the end (remember, the bigger the number at the bottom, the smaller the value). so, from least to greatest :

2 1/15 (31/15)

2 1/13 (27/13)

2 1/7 (15/7)

2 1/6 (13/6)

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where did now 2 3/8 fit in ?

well, 3/8 is almost 1/2 (so, relatively big), and we start our comparison with the biggest number in the list so far :

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let's find the smallest number that can be divided by 3 and by 8. that would be 24. so now we bring both fractions to the same base of 24.

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