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erica [24]
3 years ago
10

What is a first step to solve 6 + 7?​

Mathematics
1 answer:
frez [133]3 years ago
4 0
The first step to solve 6+7 is add
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Find the common ratio.<br><br> a2 = 7; a4 = 1575
liberstina [14]

Answer:  15

<u>Step-by-step explanation:</u>

a₁ = ___, a₂ = 7, a₃ = ____, a₄ = 1575

a₁(r) = a₂

         a₂(r) = a₃

                   a₃(r) = a₄

To get from a₂ to a₄, you have to multiply by r²

⇒  7r² = 1575

⇒  r² = 225

⇒  r = 15


7 0
3 years ago
Read 2 more answers
A farmer is purchasing hay for his cows. Before tax, one ton of hay costs $130. The farmer wants to know the total price, includ
wariber [46]

Answer:

t-120(30

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Getaway Travel Agency surveyed a random sample of 45 of their clients about their vacation plans. Of the clients surveyed, 21 ex
lana [24]
Your answer would be, What is about  241.

Simplify
516 * 21/45 

= ( 516/1) (21/45)
= (516/1) (7/15)

= (516)(7)/(1)(15)
= 3612/15

= 1204/5 (Decimal: 240.8) rounded to about 241


1204 divided by 5 equals 240, with a remainder of 4.  240 r 4, 240 4/5

Answer round to about : 241




Hope this helps!!!! Hope that what you are looking for, I tried my best to help!!!
5 0
4 years ago
Enter the coordinates of the vertex of the function f(x) = x2 + 4x - 7
elixir [45]

Given the equation of the function:

f(x)=x^2+4x-7

The given function represents a parabola

We will make a complete square to find the coordinates of the vertex

The coefficient of x = 4

Half the coefficient of x = 2

Square it give = 4

So, we will add and subtract 4

\begin{gathered} f(x)=x^2+4x+4-4-7 \\ f(x)=(x^2+4x+4)-11 \\ f(x)=(x+2)^2-11 \end{gathered}

Compare the last equation with the vertex form of the parabola

f(x)=(x-h)^2+k

So, h = -2, k = -11

So, the answer will be the coordinates of the vertex = (-2, -11)

6 0
1 year ago
Find the volume of a pyramid with a square base, where the side length of the base is
valina [46]

Answer:

Volume = 1114.1 in^3

Step-by-step explanation:

Recall that the formula for the volume of a pyramid is given by:

Volume=\frac{1}{3} \,B\,*\,H

where B is the area of the pyramid's base (in our case a square of side 12,8 in), and H the pyramid's height (in our case 20.4 in).

Then the square base of the pyramid has an area given by: (12.8\,\,in)^2=163.84\,\,in^2

Finally,we can now write the volume of the pyramid as:

Volume=\frac{1}{3} \,B\,*\,H\\Volume=\frac{1}{3} \,(163.84)\,*\,20.4\,\,in^3\\Volume=1114.112\,\,in^3

Rounding the answer to a tenth of a cubic inch, we get:

Volume = 1114.1 in^3

7 0
3 years ago
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