Answer: 600 bushels of 10% alcohol content and 400 bushels of 15% alcohol content.
Step-by-step explanation:
Let we add x quantity of 10% of alcohol content and y quantity of 15% alcohol content for making 12% of alcohol content mixture.
Then according to the question, 10% of x + 15 % of y = 12% of 1000
⇒ 0.1x + 0.15y = 120
⇒ 10x + 15y = 1200
⇒ 2x +3y = 2400 -------- (1)
And, x + y = 1000
⇒ 2x + 2y = 2000 ---------(2)
Equation 1) - equation 2)
We get y = 400
By putting the value of y in equation 1),
⇒2x + 1200 = 2400
⇒ 2x = 1200
⇒ x = 600
Thus, he needs to mix 600 bushel of 10% of alcohol content with 400 bushels of 12% of alcohol content for getting 1000 bushels of 12% of alcohol content.
Answer:
We have now seen solutions method for the three basic types of percent problems ;finding the amount, the rate, and the base
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Answer: 12,150 m²
<u>Step-by-step explanation:</u>
The ratio is 3:2 which means
Length (L) = 3x
Width (w) = 2x
Perimeter (P) = 2L + 2w
450 = 2(3x) + 2(2x)
450 = 6x + 4x
450 = 10x
45 = x
L = 3x w = 2x
= 3(45) = 2(45)
= 135 = 90
Area (A) = L × w
= 135 × 90
= 12,150
Answer:
102
Step-by-step explanation:
Since we know that the numbers are two consecutive even numbers, we can write an equation like this where n represents the 2 numbers.
n + (n+2) = 206
Simplify the left side:
n + (n+2) = 206 -----> 2n+2 = 206
Subtract 2 from both sides:
2n = 206-2 -----> 2n = 204
Now divide 204 by 2:
n = 204/2 -----> n = 102