All categories

3 years ago

HELP ME DEAR GOD-

Mathematics

1 answer:

romanna [79]3 years ago

7 0

Answer:

The probability you will get a head at least once is 50%.

Step-by-step explanation:

Since the question is asking about the probability you will get, we can assume we’re answering based on theoretical probability. This type of probability is based on logic.

A coin always has two sides, one with head and the other with tails. So we can easily represent this as half and half. 1/2 as a fraction. 0.5 as a decimal. 50% as a percent. This means that P(H) will be equal to any one of these as they are all the same. The same can be said for the probability that a head does not appear, in other words, a tail appears. The reason being that the probability is split evenly between the two. This will again mean that P(T) will equal to any one of those.

So, A = 50% and B = 50%. The probability you will get a head at least once is 50%.

You might be interested in

Two consecutive odd numbers total 32. Find the smaller.

LuckyWell [14K]

Answer:

Step-by-step explanation:

If you divide 32 by 2 you will get 16, therefore if you take the number before 16 and the number after 16 and add them together they will still equal 32. 15 + 17 = 32. The smaller number is 15.

7 0

3 years ago

Need help with figuring this out!

Genrish500 [490]

Answer:the answer is 43

Step-by-step explanation

4 0

3 years ago

Read 2 more answers

Simplify. cos^2[(pi/2) - x] + cos^2[(pi/2) - x] + cos^2x

Ipatiy [6.2K]

Numerator
cos(π/2−x)=cos(π/2)cosx+sin(π/2)sinx

now cos(π/2)=0 and sin(π/2)=1

simplifies to : 0 + sinx = sinx

Denominator

sin(π/2−x)=sin(π/2)cosx+cos(π/2)sinx

simplifies to : cosx + 0 = cosx

⇒cos(π/2−x)sin(π/2−x)=sinx/cosx=tanx

5 0

3 years ago

Will mark brainliest

Ede4ka [16]

Answer:

350

Step-by-step explanation:

7 0

3 years ago

Solve for y 16y^2-25=0

Pepsi [2]

Answer:

$\large\boxed{x=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}$

Step-by-step explanation:

$16y^2-25=0\\\\METHOD\ 1:\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\16=4^2\ \text{and}\ 25=5^2\ \text{therefore we have}\\\\4^2y^2-5^2=0\\\\(4y)^2-5^2=0\\\\(4y-5)(4y+5)+0\iff4y-5=0\ \vee\ 4y+5=0\\\\4y-5=0\qquad\text{add 5 to both sides}\\4y=5\qquad\text{divide both sides by 4}\\\boxed{y=\dfrac{5}{4}}\\\\4y+5=0\qquad\text{subtract 5 from both sides}\\4y=-5\qquad\text{divide both sides by 4}\\\boxed{x=-\dfrac{5}{4}}$

$METHOD\ 2:\\\\16y^2-25=0\qquad\text{add 25 to both sides}\\\\16y^2=25\qquad\text{divide both sides by 16}\\\\y^2=\dfrac{25}{16}\to y=\pm\sqrt{\dfrac{25}{26}}\\\\y=-\dfrac{\sqrt{25}}{\sqrt{16}}\ \vee\ x=\dfrac{\sqrt{25}}{\sqrt{16}}\\\\\boxed{y=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}$

7 0

3 years ago

Read 2 more answers