Answer:
Well it’s greater bc 23 is greater than 16
Step-by-step explanation:
I don’t know if u needed this or something else
So... get the like-terms and add/subtract

see what that gives you
Let's assume
point K as (x,y)
M is the midpoint of JK
so, other point as J(0, 11)
M(-3,2)

now, we can compare both sides
Calculation of x-coordinate:
we get


Calculation of y-coordinate:
we get



so, we will get point K
K=(-6,-7)............Answer
The answer is yes, and I will give you the calculation soon
PQ=

=

QR=

PR=

Answer:
A) y=2/3x-3
Step-by-step explanation:
A is the answer