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Anna35 [415]
3 years ago
11

A train leaves at 14:56 and arrives at 16:43. It travelled at an average speed of 135 km/h. How far did it travel? Give your ans

wer in km to 1DP.
Mathematics
1 answer:
Firlakuza [10]3 years ago
8 0

Answer:

240.8

Step-by-step explanation:

→ Calculate time taken

16:43 - 14:56 = 1 hour and 47 minutes

→ Write the speed formula and make distance the subject

Speed = Distance ÷ Time ⇔ Distance = Speed × Time

→ Convert 1 hour and 47 minutes into decimal format

1.78333333 or  1\frac{47}{60}

→ Substitute values into formula

135 ×  1\frac{47}{60}  = 240.75

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Answer:

201.06

Step-by-step explanation:

A=πr2=π·82≈201.06193

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Would it be -1/3x -2?
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MN is a diameter of a circle with centre ' O ' . If BD = CD , prove that ∠OAD = ∠OCD
Varvara68 [4.7K]

Answer:

\sf \: Proved \: \angle \: OAD  \:  =  \angle \: OCD

Step-by-step explanation:

<em>Given:</em>

Mn is diameter of circle having centre O

and BD = OD,

<em><u>To prove that:</u></em>

<u>\angle \: OAD  \:  =  \angle \: OCD</u>

<em>Solution:</em>

Join the points O and B and draw OB,

On joining the line,

in ∆OCD and ∆OBD,

OC =OB → (Radius of same circle)

BD =CD → (from given)

OD =OD → (Common side in both the triangles)

Hence ∆OCD and ∆OBD are congruent from SSS property.

so we can say that,

\angle \: OBD  \:  =  \angle \: OCD

Consider above prove as statement A

Corresponding angles of congruent traingle.

in ∆ OAB,

OA = OB (radius of same circle)

hence ∆OAB is an isosceles traingle.

We know that opposite angle of isosceles traingle are always equal. hence,

\angle \: OBD  \:  =  \angle \: OAB \\ \angle \: OAB  \:  =  \angle \: OAD (same \: angles) \\ \angle \: OBD  \:  =  \angle \: OAD

Consider above prove as statement B

From Statement A & B we can say that

\angle \: OAD  \:  =  \angle \: OCD

<em>Thanks for joining brainly community!</em>

5 0
2 years ago
Y=2x+5 and y=3x+11 solve by substitution.
kondaur [170]

Answer:

Answer: x= -6 and y= -7

Step-by-step explanation:

Substitute 2x+5 for y in y=3x+11:

y=3x+11

2x+5=3x+11

2x+5+−3x=3x+11+−3x(Add -3x to both sides)

−x+5=11

−x+5+−5=11+−5(Add -5 to both sides)

−x=6

−x−1=6−1(Divide both sides by -1)

x=−6

Step: Substitute −6 for x in y=2x+5:

y=2x+5

y=(2)(−6)+5

y=−7(Simplify both sides of the equation)

-Source: MathPapa

6 0
3 years ago
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