1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Snowcat [4.5K]
3 years ago
13

Which is the solution to the equation 2.6a+18.4=28.8? 1.4418.227​

Mathematics
1 answer:
Elenna [48]3 years ago
6 0
The solution to this problem is a=4
You might be interested in
What is %65/.096 + 8/0.9?
Artemon [7]
15.66 is what I got in my calculator if you turn %65 into .65
8 0
3 years ago
Write the point-slope form of the equation of the line passing through the points (-5, 6) and (0, 1).
ludmilkaskok [199]
Slope of the line
(6-1) / (-5-0)
5 / -5
-1

General equation of the line
y = -x + c
if this passes through (0,1)
0 = (-1*1) + c
c = 1

so the equation is
y = -x + 1
5 0
3 years ago
ILL MARK U BRAINLIEST PLS HELP ME WITH THIS
Zinaida [17]
51 cm your welcome hehehe
8 0
3 years ago
△ABC  is a right triangle with right angle C. Side AC is 6 units longer than side BC . If the hypotenuse has length 52–√ units,
Evgesh-ka [11]

Answer:

AC = 7.12 units

Step-by-step explanation:

A right triangle has two legs and a hypotenuse. The hypotenuse is opposite the right angle. As Angle C is the right angle, then the triangle can be constructed as shown in the picture attached. The sides of the triangle have a relationship known as the Pythagorean Theorem a² + b² = c². In the theorem, the legs of the triangle are a and b while the hypotenuse is c. Substitute a = x, b = x+6, and c = √52. Simplify and solve.

a² + b² = c²

x² + (x+6)² = √52²

x² + x² + 12x + 36 = 52

2x² + 12x - 16 = 0

You can use the quadratic formula to solve by substituting a = 2, b = 12, and c = -16.

The quadratic formula is x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}.

Substitute and you'll have:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-12+/-\sqrt{12^2-4(2)(-16)} }{2(2)}=\frac{-12+/-\sqrt{144+128} }{4)}

\frac{-12+/-\sqrt{272} }{4}=\frac{-12+/-16.5 }{4} = 1.12, 7.13

Only 1.12 is a solution since 7.13 will not satisfy the Pythagorean theorem

Side AC is 6 units longer than side BC. This means x = BC and AC = x + 6.

AC = 1.12 + 6 = 7.12

6 0
4 years ago
Yuri thinks that 3/4 is a root of the following function.
sineoko [7]

Given:

The polynomial function is

q(x)=6x^3+19x^2-15x-28

Yuri thinks that \dfrac{3}{4} is a root of the given function.

To find:

Why \dfrac{3}{4} cannot be a root?

Solution:

We have,

q(x)=6x^3+19x^2-15x-28

If \dfrac{3}{4} is a root, then the value of the function at \dfrac{3}{4} is 0.

Putting x=\dfrac{3}{4} in the given function, we get

q(\dfrac{3}{4})=6(\dfrac{3}{4})^3+19(\dfrac{3}{4})^2-15(\dfrac{3}{4})-28

q(\dfrac{3}{4})=6(\dfrac{27}{64})+19(\dfrac{9}{16})-\dfrac{45}{4}-28

q(\dfrac{3}{4})=3(\dfrac{27}{32})+\dfrac{171}{16}-\dfrac{45}{4}-28

q(\dfrac{3}{4})=\dfrac{81}{32}+\dfrac{171}{16}-\dfrac{45}{4}-28

Taking LCM, we get

q(\dfrac{3}{4})=\dfrac{81+342-360-896}{32}

q(\dfrac{3}{4})=\dfrac{-833}{32}\neq 0

Since the value of the function at \dfrac{3}{4} is not equal to 0, therefore, \dfrac{3}{4} is not a root of the given function.

4 0
3 years ago
Other questions:
  • Pls someone help, ill give ya brainliest :D
    13·1 answer
  • what is the average rate of change for the quadratic function from x=4 and x=8? enter your answer in the box
    5·2 answers
  • What is the answer to 45 times 61
    11·2 answers
  • April has two favorite numbers. If you add her favorite numbers, you get 26. If you multiply her favorite numbers, you get 144.
    10·1 answer
  • What is 3425 x 10^-2 ?
    6·2 answers
  • Lana bought a bamboo plant that was
    6·1 answer
  • Help me please thank u very much
    11·2 answers
  • There are 75 balloons in each package. How many balloons are in 20 packages​
    11·2 answers
  • 1/2 divided by n = 1/8
    6·1 answer
  • Find the range of the data.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!