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VladimirAG [237]
3 years ago
8

What is %65/.096 + 8/0.9?

Mathematics
1 answer:
Artemon [7]3 years ago
8 0
15.66 is what I got in my calculator if you turn %65 into .65
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Please help in this question. I WILL mark brainliest. NO LINKS
deff fn [24]

Answer:

B, you are correct

Area of the bigger trapezoid = (6 + 2) x 1/2 x 6 = 8 x 1/2 x 6 = 4 x 6 = 24

Area of the smaller trapezoid = (4 + 2) x 1/2 x 3 = 6 x 1/2 x 3 = 3 x 3 = 9

<h2>Area of the shaded area = 24 - 9 = 15</h2>

<em>Hope that helps! :)</em>

<em>Hope that helps! :)</em>

<em></em>

<em>-Aphrodite</em>

Step-by-step explanation:

6 0
3 years ago
Please help me with this i will mark brainliest<br><br><br><br><br>QUICK!!!!!!
Yanka [14]

Answer:

w - 3.3 + -3.3 = 5.6 - 3.3

w = 2.3

3 0
3 years ago
Simplify <br> 1+sinx/cosx+cosx/1+sinx
Dmitry [639]
\frac{1 + sin(x)}{cos(x)} + \frac{cos(x)}{1 + sin(x)}
\frac{[1 + sin(x)][1 +sin(x)]}{cos(x)[1 + sin(x)]} + \frac{cos(x)[cos(x)]}{cos(x)[1 + sin(x)]}
\frac{1 + 2sin(x) + sin^{2}(x)}{cos(x)[1 + sin(x)]} + \frac{cos^{2}(x)}{cos(x)[1 + sin(x)]}
\frac{1 + 2sin(x) + sin^{2}(x) + cos^{2}(x)}{cos(x)[1 + sin(x)]}
\frac{1 + 2sin(x) + 1}{cos(x)[1 + sin(x)]}
\frac{1 + 1 + 2sin(x)}{cos(x)[1 + sin(x)]}
\frac{2 + 2sin(x)}{cos(x)[1 + sin(x)]}
\frac{2[1 + sin(x)]}{cos(x)[1 + sin(x)]}
\frac{2}{cos(x)}
2sec(x)
6 0
3 years ago
Solve the inequality IxI &lt; 5​
Elodia [21]

Answer:

the correct answer is the second one

3 0
3 years ago
I would like all the help I can’t get pleaseee
expeople1 [14]

Answer:

Step-by-step explanation:

a=4    b=12

2a+3b=

2*4+3*12=

8+36=

44

a²-b+10=

4²-12+10=

4*4-2=

16-2=

14

(ab)²-(a+b)²=

(4*12)²-(4+12)²=

48²-16²=

(48+16)(48-16)=

64*32=

2048

7 0
2 years ago
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