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2 years ago

Jeanette added $161.50 to her savings account when she got paid. If the new balance is $875.80, what was the prior balance?

Mathematics

1 answer:

Salsk061 [2.6K]2 years ago

4 0

Answer:

Step-by-step explanation

714.30 was the prior balance

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Indira is using a number line to add Negative 1 + (negative 3). She begins by showing –1 on the number line, as shown below.

jarptica [38.1K]

Answer= -4

-1+-3=-4

Step by step-
Add like normal then add the sign since both numbers are negative.
3+1= 4 then add the sign

7 0

3 years ago

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I would appreciate the help on all of these :)

Maurinko [17]

Answer:

Pythagoras theorem states that c²=a²+b²

14²=12²+x²

14²-12²=x²

196-144=x²

52=x²

√52=√x²

7.2111025509279785=x

rounded up to the nearest hundredth=7.21

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3 years ago

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Which expression is equivalent to -51 - (-60)−51−(−60)minus, 51, minus, left parenthesis, minus, 60, right parenthesis?

djyliett [7]

Answer:

it's B.

Step-by-step explanation:

5 0

2 years ago

Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab

Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

$\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

<u>Right part:</u>

$\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

Since simplified left and right parts are the same, then the equality is true.

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3 years ago

I need help please!!!

solniwko [45]

Answer:

I dont know what you mean wdym...

Step-by-step explanation:

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3 years ago