We calculate for the x- and y-components of the distances traveled by the clown.
First: 8.0 m north
x-component = 0 m
y-component = +8 m
Second: 55° north of east (3.5 m)
x-component = (3.5 m)(cos 55°) = 2 m
y-component = (3.5 m)(sin 55°) = 2.87 m
Third: 5 m east
x-component = 5 m
y-component = 0 m
The total x-component is equal to 7 m and the y-component is equal to 10.87 m.
The displacement is,
c = sqrt((7 m)² + (10.87 m)²)
c = 12.93 m
<em>Answer: 12.93 m</em>
Answer:
The proximate distance is 3,-2
All we have to do here is to express numbers 40 and 5 in each of equations. Note that first number in brackets is always x coordinate and second number is y coordinate
First equation:
5 = 40*8 false
Second
5 = 5*40 false again
Third:
5 = 40/8 = 5 True
checking for just in case last one:
5 = 40/5 = 8 False
Correct one is C)
It would be 210,000 cause 2.5x20 = 50% so 420,000 x 50%
Answer:
4 + 13y
Step-by-step explanation: