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bearhunter [10]
3 years ago
5

Researchers studying the sticky droplets found on spider webs will measure the widths of a random sample of droplets. From the s

ample, the researchers will construct a 95 percent confidence interval to estimate the mean width of all such droplets. Write the correct statement about a 95 percent confidence interval for the mean width.
Mathematics
1 answer:
Leno4ka [110]3 years ago
3 0

Answer:

The interval will be narrower if the researchers increase the sample size of droplets.

Step-by-step explanation:

The confidence interval can be obtained using the relation :

Xbar ± Margin of error

Margin of Error = Zcrit * s/sqrt(n)

Zcritical = critical vlaue at the specified α - level

n = sample size ; s = standard deviation

Sample size being the denominator, will reduce the overall value of the error margin as we utilize a larger sample.

Hence, the interval becomes narrower as the error margin is reduced which is achieved by employing an increased sample size.

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Elena-2011 [213]
A graphing calculator can be helpful for these.

A) Since neither inequality includes the "or equal to" case, the boundary line for the solution set is a dashed line. For the first inequality, the shading is above the line; for the second, the shading is below the line. The solution set is points to the right of perpendicular lines with slope -2 and +1/2 through point (2, -1).

B) The point -2, 3 satisfies, neither inequality.
.. 3 > -2(-2) +3 . . . FALSE
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6 0
4 years ago
To arrive at its destination on time the bus should have maintained a speed of vv kilometers per hour throughout the journey. In
yulyashka [42]

Answer:

The answer to the question is

The actual duration of the trip is 8/9 times the normal duration or the bus arrived 1/9 times earlier than it would have at a constant speed of v kph

Step-by-step explanation:

Speed of bus in the first third distance = v kph

Speed of bus for the remaining two thirds = 1.2 v kph

To solve the question, we note that speed = distance/time

therefore time = distance/speed

Let the distance of the destination be D, then

Normal duration at speed v = D/v

Actual duration (D/3)÷v + (2D/3)÷(1.2v) ⇒ (1.2*D/3 + 2D/3)1.2v

= \frac{D}{3v} +\frac{5D}{9v} = (8/9)×D/v

Therefore the actual duration is 8/9 times the normal duration

7 0
4 years ago
Solve for x : sq.root(2x^2 + 1)=2
kondor19780726 [428]

Answer:

x=3

Step-by-step explanation:

6 0
3 years ago
A chef cooked 7 kilograms if the guests only ate 3 quaters of the amount he cooked how much did they eat
Oduvanchick [21]

5.25 kilograms.

3 quarters = 3/4

7 divided by 4 is 1.75

1.75x3 is 5.25.

6 0
3 years ago
Tom simplified an expression in three steps, as shown below:
Ivan

Answer: a

Step-by-step explanation: process of elimination basically.

5 0
3 years ago
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