A graphing calculator can be helpful for these.
A) Since neither inequality includes the "or equal to" case, the boundary line for the solution set is a dashed line. For the first inequality, the shading is above the line; for the second, the shading is below the line. The solution set is points to the right of perpendicular lines with slope -2 and +1/2 through point (2, -1).
B) The point -2, 3 satisfies, neither inequality.
.. 3 > -2(-2) +3 . . . FALSE
.. 3 < 1/2(-2) -2 . . .FALSE
Answer:
The answer to the question is
The actual duration of the trip is 8/9 times the normal duration or the bus arrived 1/9 times earlier than it would have at a constant speed of v kph
Step-by-step explanation:
Speed of bus in the first third distance = v kph
Speed of bus for the remaining two thirds = 1.2 v kph
To solve the question, we note that speed = distance/time
therefore time = distance/speed
Let the distance of the destination be D, then
Normal duration at speed v = D/v
Actual duration (D/3)÷v + (2D/3)÷(1.2v) ⇒ (1.2*D/3 + 2D/3)1.2v
=
= (8/9)×D/v
Therefore the actual duration is 8/9 times the normal duration
Answer:
x=3
Step-by-step explanation:
Answer: a
Step-by-step explanation: process of elimination basically.