Answer:
Step-by-step explanation:
we know that
In this problem ABCD is a rectangle
so
DC=AB
BC=AD
Let
BC ---> the length of rectangle
DC ---> the width of rectangle
we know that
The perimeter of rectangle is equal to
we have
so
simplify
----> equation A
----> equation B
substitute equation B in equation A
Solve for BC
Combine like terms
Divide by 3 both sides
<em>Find the value of DC</em>
----> 
Remember that
DC=AB
therefore
(a-b)^2 = a^2-2ab+b^2
(8-5i)^2 = 8^2-2(8)(5i)+(5i)^2
= 64-80i+25i^2
i^2=-1
So
= 64-80i+25(-1)
=64-25-80i
= <em><u>39 - 80i</u></em>
which is your answer :)
Step-by-step explanation:
number 1 is 68 degrees Fahrenheit and number 2 is 98.6=37 degrees Celsius and 102 fahrenheit is higher than the normal
<h3>I'll teach you how to solve 5k^3-8-4k^2+5k^2-2+3k^3</h3>
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5k^3-8-4k^2+5k^2-2+3k^3
Group like terms:
5k^3+3k^3-4k^2+5k^2-8-2
Add similar elements:
5k^3+3k^3+k^2-8-2
Add similar elements:
8k^3+k^2-8-2
Subtract the numbers:
8k^3+k^2-10
Your Answer Is 8k^3+k^2-10
Plz mark me as brainliest :)
