The answer to this question is 3
Answer:
d(m) = (1.05 miles/min)*m
Step-by-step explanation:
Divide 2 5/8 miles by 3 1/2 minutes to obtain the unit rate (miles per minute):
2 5/8 miles
--------------------
3 1/2 minutes
First, convert 2 5/8 miles and 3 1/2 minutes to improper fractions:
21/8 miles 21/8 miles
------------------ = ---------------------- = 21/20 miles/minute
5/2 minutes 20/8 minutes
The constant rate is (21/20) miles/minute, or 1.05 miles/minute.
Thus, the equation representing the distance, d, that the car travels in m minutes is
d(m) = (1.05 miles/min)*m
To find an outlier, multiply the IQR by 1.5
172,500 * 1.5 = 258,750
now, u add that to Q3.....545,000 + 258,750 = 803,750....anything above this number is an outlier
now,u subtract that from Q1....372,500 - 258,750 = 113,750....anything below that is an outlier
u have already done this...u have found the higher end and the lower end....so anyting larger then the higher end or lower then the lower end is ur outlier
so in ur data, there is only 1 outlier and that is 933.....130 is not an outlier because it is not less then 113,750.
Ratio of:
Lambs 5:24
Rabbits 11:24
Goats 4:24
Piglets 4:24
