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3 years ago

In the figure below, m show work i’ll make you brainliest plz help

Mathematics

1 answer:

anzhelika [568]3 years ago

6 0

We need the picture to answer so if you could take a picture and put it on the question

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How much greater is the sum of the interior angles of a decagon the song of the interior angles of a quadrilateral

slega [8]

Answer: 1080 degrees

Step-by-step explanation:

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2 years ago

Luke makes fruit cakes for a stall at a village fete. It costs Luke £1.80 for

zalisa [80]

Answer:

2.43

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1.80 x 0.35 + 1.80

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3 years ago

What were the three parts to Hamilton's financial plan ?

earnstyle [38]

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3 years ago

8.25 × 10–4 in standard form.

Elanso [62]

The 10^-4 means that the decimal point is 4 places to the left of where it is in 8.25 (if the exponent was positive the decimal point would be to the right). If you move the decimal point 4 places to the left you get an answer of 0.000825 which is 8.25 * 10^-4 in standard form.

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3 years ago

The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth

Art [367]

Answer:

a) $N_0=250\; k=0.15$

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies $t=0$ . And $N(0)=N_0$ . The process is:

$N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250$

b) After 2 days means $t=48$ . So, we just replace and operate:

$N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}$

c) $N(t_1)=4000; \;t_1=?$

$N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\ \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h$

d) $t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)$

$N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h$

6 0

3 years ago