Question

Please help!! I only have 30 minutes left!! Given that x and y are positive integers and (x·2)+x(2^2)+(y·2^3)+(y·2^4)=42, what is the value of xy?

Answer 1

Answer:

xy = 3

Step-by-step explanation:

The expression to be evaluated is:

$2\cdot x +4\cdot x + 8\cdot y + 16\cdot y = 42$

$6\cdot x + 24\cdot y = 42$

By some algebraic handling:

$6\cdot (x + 4\cdot y) = 42$

Where:

$x+4\cdot y = 7$

There is one possible solution:

x = 3, y = 1

And consequently,

xy = 3