Answer:
BH= 108 --> 1st until 6th space
so, 108/6 = 18 for each space
DE...?
DE only use 1 space so the answers is 18 unit
I hope this helps^_^
Answer:
28.6, that is, about 29 are expected to be defective
Step-by-step explanation:
For each battery, there are only two possible outcomes. Either it is defective, or it is not. The probability of a battery being defective is independent of other betteries. So the binomial probability distribution is used to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:

The probability that a battery is defective is 1/14.
This means that 
400 batteries.
This means that 
How many are expected to be defective?

28.6, that is, about 29 are expected to be defective
Answer:
24 m^2
Step-by-step explanation:
There are two areas to consider here: first, the area of the wall, and second, the area of the window. We answer this question by finding these two areas and subtracting the area of the window from the area of the wall.
Wall area: (4 m)(7 m) = 28 m^2
Window area: (2 m)(2 m) = 4 m^2
Net area of wall, to be covered in brick:
28 m^2 - 4 m^2 = 24 m^2
V(cylinder)=πR²H
Radius of the cylinder R=x, height of the cylinder H=y.
We can write for the cylinder
V(cylinder)=πx²y
V(cone) =(1/3)πr²h
Radius of the cone r=2x.
We can write for the cone
V(cone)= (1/3)π(2x)²h=(1/3)π *4*x²h
V(cylinder) =V(cone)
πx²y=(1/3)π *4*x²h
y=(4/3)*h
h=(3/4)*y
Answer:
x= -2
Step-by-step explanation: