Work out the height of this triangle
3 answers:
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In a circle, the measure of an inscribed angle is half the measure of the intercepted arc.
∠BCD = arc BAD/2 ⇒ arc BAD = 2*∠BCD = 2*100 = 200°
arc BCD = 360° - arc BAD = 360° - 200° = 160°
∠d = arc BCD/2 = 160/2 = 80°
∠BCD = arc BAD/2 ⇒ arc BAD = 2*∠BCD = 2*100 = 200°
arc BCD = 360° - arc BAD = 360° - 200° = 160°
∠d = arc BCD/2 = 160/2 = 80°