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3 years ago

(x + 2)(x + 3)(x + 4) can be written in the form x + ax² + bx + c

Mathematics

1 answer:

ELEN [110]3 years ago

5 0

Answer:

$a=9, b=26, c=24$

Step-by-step explanation:

Let's expand the expression bit by bit.

$(x+2)(x+3)=(x)(x)+(x)(3)+(2)(x)+(2)(3)=x^2+5x+6$ by FOIL.

We have that $(x^2+5x+6)(x+4)=x(x^2+5x+6)+4(x^2+5x+6)=x^3+5x^2+6x+4x^2+20x+24=x^3+9x^2+26x+24$ .

So, the answer is $\boxed{a=9, b=26, c=24}$

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Eduardwww [97]

The cost of each ribeye steak dinner is $ 29 and cost of each grilled salmon dinner is $ 20

Solution:

Let "a" be the cost of each ribeye steak dinners

Let "b" be the cost of each grilled salmon dinners

A waitress sold 11 ribeye steak dinners and 12 grilled salmon dinners, totaling $560.63 on a particular day

Thus we frame a equation as:

11 x cost of each ribeye steak dinners + 12 x cost of each grilled salmon dinners = 560.63

$11 \times a + 12 \times b = 560.63$

11a + 12b = 560.63 -------- eqn 1

Another day she sold 16 ribeye steak dinners and 6 grilled salmon dinners, totaling $584.46

Thus we frame a equation as:

16 x cost of each ribeye steak dinners + 6 x cost of each grilled salmon dinners = 584.46

$16 \times a + 6 \times b = 584.46$

16a + 6b = 584.46 ------------ eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 2 by 2

32a + 12b = 1168.92 ------- eqn 3

Subtract eqn 1 from eqn 3

32a + 12b = 1168.92

11a + 12b = 560.63

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21a = 1168.92 - 560.63

21a = 608.29

Divide both sides by 21

$a = 28.96 \approx 29$

Substitute a = 29 in eqn 1

11(29) + 12b = 560.63

319 + 12b = 560.63

12b = 560.63 - 319

12b = 214.63

Divide both sides by 12

$b = 20.13 \approx 20$

Thus cost of each ribeye steak dinner is $ 29 and cost of each grilled salmon dinner is $ 20

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