Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
Both triangle are isosceles, which means their base angles are congruent.
54 + 2y = 180
2y = 126
y = 63
The measure of the base angles of the triangle on the left is 63 degrees.
180 - 63 = 117
117 + 2x = 180
2x = 63
x = 31.5
Answer:
x = 31.5
Hope this helps.
<span>309,058,304 hope this helps!!
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Answer:
its 288 if u search formula for surface area of a rectangular prism
Step-by-step explanation:
Answer:
Step-by-step explanation:
(168 mi)/(7 hr) = (24 mi)/hr
(2.5 hr) × (24 mi)/hr = 60 mi
