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pantera1 [17]
4 years ago
10

|x| + 5 = 18A. 5 or -5B. 13 or -13C. 18 or -18D. 23 or -23

Mathematics
2 answers:
lana [24]4 years ago
6 0
The correct answer is b
Vilka [71]4 years ago
5 0
Its b hope this helped

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If a girl lifts a load of 60N to a height of 3m, find work. ​
taurus [48]

Let the mass of the object exists at 60 N and the height exists at 3m then work

exists in 1764.

What is work?

The work done by a force exists determined to be the product of a component of the force in the direction of the displacement and the magnitude of this displacement.

Work can be estimated by multiplying Force and Distance in the direction of force as follows.

W = F × d. Unit.

Given data:

m = mass of the object = 60 N

h = height = 3 m

Work = Fh = mgh

g = gravity = 9.8 m/s²

work = Fh = mgh

= 60*3*9.8

= 1764

Therefore, the work exists in 1764.

To learn more about work refer to:

brainly.com/question/15908595

#SPJ9

5 0
1 year ago
i have 100% in the class, but the cumulative final is next week. what if i fall on the final, how many percent will i have after
Alex

Answer:

How much will a 60 affect my grade?

If it is a test grade, which in my school they are worth 60%, then it will bring you down by pretty much a whole lot, probably about 7–10 points. If it is a 20% weight it will only bring it down by about 2–3 points.

Step-by-step explanation:

8 0
2 years ago
Anybody help me to solve this question. ​
Mumz [18]

Answer:

\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)} are\ in\ AP

Step-by-step explanation:

Given that (b-c)^2, (c-a)^2 , (a-b)^2 are in AP

To prove: \dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)} are in AP

From given as we know if p , q, r are in AP then 2q= p+r.

2(c-a)^2= (b-c)^2+(a-b)^2\\\\\Rightarrow 2(c^2+a^2-2ac)=b^2+c^2-2bc+a^2+b^2-2ab\\\\\Rightarrow 2c^2+2a^2-4ac= 2b^2+c^2+a^2 -2bc-2ab\\\\\Rightarrow a^2+c^2-2b^2-4ac= -2bc-2ab\\\\\Rightarrow a^2-2b^2+c^2= 4ac-2bc-2ab

Now

\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)}2\dfrac{1}{(c-a)} =\dfrac{1}{(b-c)}+\dfrac{1}{(a-b)}\\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-b+b-c}{(b-c)(a-b)} \\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-c}{(b-c)(a-b)} \\\\\Rightarrow2(b-c)(a-b) = (c-a)(a-c) \\\\\Rightarrow 2(ab-b^2-ac+bc)= -(a-c)^2\\\\\Rightarrow 2ab- 2b^2-2ac+2bc = -a^2-c^2+2ac\\\\\Rightarrow a^2-2b^2+c^2=4ac-2ab-2bc

Which is the result of AP

.

Hence proved

6 0
3 years ago
Every number other than 0 has a multiplicative inverse.
Gala2k [10]

Answer:

A multiplicative inverse of a real number x is a real number y such that xy = 1. ... ((NOT GOOGLING DEF))

Step-by-step explanation:

"For every real number x, if x 0, then there is a real number y such that xy = 1.”

3 0
3 years ago
Please, please help with this question!! I don't understand it!
Kazeer [188]

Answer:

Step-by-step explanation:

Find the area of each shape, then multiply by 20, then round to nearest hundred.

Half circle:

=πr²/2

=50π

=157.08

Large square:

=L•w

=20(22)

=440

Small square:

=L(w)

=12(3)

=36

Triangle:

=b(h)/2

=8(3)/2

=12

Btu req:

=(157.08+440+36+12)(20)

=(645.08)(20)

=12901.6

=12900 BTU

3 0
3 years ago
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