3 years ago

In the illustration below, Picture 4 represents...

Biology

1 answer:

igor_vitrenko [27]3 years ago

8 0

Answer:

i think it's A i'm not 100% sure let me know if it's right

Explanation:

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All animals can trace their lineage to a common ancestor that lived in the _____.

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In the Neoproterozoic era. hope this helps

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3 years ago

A genetic engineer wants to modify a virus to insert a synthetic gene into human lung cells. Which modified viruses would achiev

KatRina [158]

Answer:

D) A bacteriophage that has been modified to carry the gene.

Explanation:

To achieve her goal, she should use (d) A bacteriophage that has been modified to carry the gene. Bacteriophage are diverse group of viruses which are easily manipulated.

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3 years ago

True or False: Most familiar life forms live in regions of biomes that humans inhabit.

Studentka2010 [4]

TRUE hope that helps!

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4 years ago

An autosomal recessive disease has an incidence of 1/10,000. What is the approximate frequency of heterozygote carriers for this

goblinko [34]

Answer:

Option B

Explanation:

Given

Number of incidences or frequency of an autosomal recessive disease $= \frac{1}{10000}$

As per Hardy Weinberg's equation, frequency of a recessive genotype is $q^{2}$

$q = \sqrt{\frac{1}{10000} }\\ q = \frac{1}{100}$

As per first equation of Hardy Weinberg's -

$p+q=1$

so ,

$p = 1-q\\p = 1-\frac{1}{100}\\p = \frac{99}{100}$

$p^2 = (\frac{99}{100})^2\\p^2 =\frac{9801}{1000}$

As per second equation of Hardy Weinberg's -

$p^{2} + q^{2} + 2pq=1$

Substituting the given values in above equation, we get -

$\frac{9801}{10000} + \frac{1}{100} + 2pq=1\\2pq = 1-(\frac{9801}{10000} + \frac{1}{100})\\2pq = 0.99%\\OR[tex]2pq=1$ %

$2pq = \frac{1}{100}$

Hence, option B is correct.

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3 years ago

Which process do seeds undergo under favorable conditions?

Sergeeva-Olga [200]

Answer is Pollination

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3 years ago