$The\ slope-point\ form:y-y_1=m(x-x_1)\\The\ slope-intercept\ form:y=mx+b\\--------------------\\m=-3;\ (4;\ 4)\to x_1=4\ and\ y_1=4\\\\\boxed{y-4=-3(x-4)}\\\\y-4=-3x+12\ \ \ |add\ 4\ to\ both\ sides\\\boxed{y=-3x+16}$

7 0

3 years ago

A coin is tossed four times What is the probability of getting four heads? (1 mark) a) b) What is the probability of getting exa

BlackZzzverrR [31]

<h2>Answer:</h2>

1. A coin is tossed four times. What is the probability of getting four heads?

Each toss has a 1/2 chance of getting a head.

So the chance of getting all four heads can be calculated as :

$1/2\times1/2\times1/2\times1/2=1/16$

2. A coin is tossed four times. What is the probability of getting two heads?

Each toss can have 2 results, so 4 flips will have $2^{4}$ or 16 results.

Getting two heads means getting two tails also. So, we can get the number of times two heads come = $\frac{4!}{2!2!}$ = 6

We can write the groups like - {HHTT,HTHT,HTTH,THHT,THTH,TTHH}

So, the required probability is : 6/16 or 3/8.

3. Not getting two heads means getting 3 tails and 1 head or all tails.

Probability of having all tails = $1/2\times1/2\times1/2\times1/2=1/16$

Probability of one head(1st trial) and three tails = 1/16

Probability of one head (2nd trial) and three tails (the 1st, 3rd and 4th trials) = 1/16

Probability of one head (3rd trial) and three tails (the 1st, 2nd and 4th trials) = 1/16

Probability of one head (4th trial) and three tails (the 1st, 2nd and 3rd trials) = 1/16

So, the total probability showing only one or none head and at least three tails = $1/16+1/16+1/16+1/16+1/16=5/16$

6 0

3 years ago

Explain how you can tell that 31/33 is in simplest form

shtirl [24]

Well 31 is not able to go any were and it has to stay 31

3 0

2 years ago

Read 2 more answers

Please hurry please & thank you

Mama L [17]

All rhombuses have 2 pairs of parallel sides.

7 0

3 years ago