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dexar [7]
3 years ago
15

3.1.3 How far was the hiker at 10:30?

Mathematics
1 answer:
umka21 [38]3 years ago
5 0

Answer:

y = 1400 + 5.2x --- Running cost

y = 25 x --- Monthly income

71 cars

R1775

Step-by-step explanation:

Given

Expenses

Salaries = 1400.00

Others = 5.20 per car

Income

Rate = 25.00 per car

Solving (a): Expression for the running cost

This is calculated as:

y = Salary + Others * x

Where

y = Total running cost

x = number of cars

So:

y = 1400 + 5.20 * x

y = 1400 + 5.2x

Solving (b): Expression for monthly income

This is calculated as:

y = Rate * x

Where

y = Total income

x = number of cars

So:

y = 25.00 * x

y = 25 x

Solving (c): Break even

To do this, we equate the expressions in (a) and (b)

y = y

25x = 1400 + 5.2x

Collect Like Terms

25x -5.2x= 1400

19.8x= 1400

Solve for x

x = \frac{1400}{19.8}

x = 71

Solving (d): How much to break even

Substitute 71 for x in any of (a) or (b)

y = 25 x

y = 25 * 71

y = 1775

<em>Solving (e): There is no question to answer on the "graph"</em>

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Answer:

\frac{729}{64}

Step-by-step explanation:

The given expression is

(\frac{3a^{-3}b^{2}  }{2a^{-1} b^{0} } )^{2}

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When we say "evaluate the expression" refers to replacing the given values in the expression. Then, we solve each power in the numerator and denominator. After that, we solve each product in the fraction. At the end, we apply the square power. As follows

(\frac{3a^{-3}b^{2}  }{2a^{-1} b^{0} } )^{2}=(\frac{3(-2)^{-3}(-3)^{2}  }{2(-2)^{-1} (-3)^{0} } )^{2}=(\frac{3(\frac{1}{-8})(9)}{2(\frac{1}{-2} (1))} )^{2} =(\frac{-\frac{27}{8} }{-1} )^{2} =\frac{27^{2} }{8^{2} } =\frac{729}{64}

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3 years ago
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Answer:

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Step-by-step explanation:

7 0
3 years ago
Multiply by using suitable rearrangement: 2 × 4 × 8 × 50 × 125. I need this answer. Quick. Ok, How about I give 15 points? Yeah
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Answer:

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Select the correct answer.
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Answer:

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Step-by-step explanation:

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3 years ago
1.An ice cream cone has a radius of 3 inches and a height of 5 inches. Which measurement is the closest to the volume in cubic i
Murljashka [212]
First question
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Second qustion
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3 years ago
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