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dexar [7]
3 years ago
15

3.1.3 How far was the hiker at 10:30?

Mathematics
1 answer:
umka21 [38]3 years ago
5 0

Answer:

y = 1400 + 5.2x --- Running cost

y = 25 x --- Monthly income

71 cars

R1775

Step-by-step explanation:

Given

Expenses

Salaries = 1400.00

Others = 5.20 per car

Income

Rate = 25.00 per car

Solving (a): Expression for the running cost

This is calculated as:

y = Salary + Others * x

Where

y = Total running cost

x = number of cars

So:

y = 1400 + 5.20 * x

y = 1400 + 5.2x

Solving (b): Expression for monthly income

This is calculated as:

y = Rate * x

Where

y = Total income

x = number of cars

So:

y = 25.00 * x

y = 25 x

Solving (c): Break even

To do this, we equate the expressions in (a) and (b)

y = y

25x = 1400 + 5.2x

Collect Like Terms

25x -5.2x= 1400

19.8x= 1400

Solve for x

x = \frac{1400}{19.8}

x = 71

Solving (d): How much to break even

Substitute 71 for x in any of (a) or (b)

y = 25 x

y = 25 * 71

y = 1775

<em>Solving (e): There is no question to answer on the "graph"</em>

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3 years ago
 Triangle PQR has two known interior angles of 24°, and 100°.
Tamiku [17]
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3 0
3 years ago
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(ASAP PICTURE ADDED) What is the simplified form of the following expression?
bonufazy [111]

Answer:

option c is correct.

Step-by-step explanation:

7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)

WE need to simplify this equation.

Solve the parenthesis of each term.

=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right

Now, We will find factors of the terms inside the square root

factors of 2: 2

factors of 16 : 2x2x2x2

factors of 8: 2x2x2

Putting these values in our equation:=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)

Adding like terms we get:

=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right\\=(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\

(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\can\,\,be \,\, written\,\, as\,\,\\(\sqrt[3] {2x})-6\left(\sqrt[3]{x}\right)

So, option c is correct

5 0
3 years ago
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