A ↔ B ↔ C ↔ D ↔ E ↔ F
8 7 
???
AB + BC + CD = AD <em>segment addition postulate</em>
+ 8 + 7 = AD
+ 15 = AD
AD + 60 = 4AD
60 = 3AD
20 = AD
AB = = 
= 5
DE = 
= 
= 4
CD + DE + EF = CF <em>segment addition postulate</em>
7 + 4 + EF = CF
11 + EF = CF
Answer: 11 + EF
Note: You did not provide any info about EF. If you have additional information that you did not type in, calculate EF and add it to 11 to find the length of CF.
In general, the sum of the measures of the interior angles of a quadrilateral is 360. This is true for every quadrilateral. This does not help here, because there are two angles (angles B and D) we know nothing about. We only know about opposite angles A and C.
In this case, you can use another theorem.
Opposite angles of an inscribed quadrilateral are supplementary.
m<A + m<C = 180
3x + 6 + x + 2 = 180
4x + 8 = 180
4x = 172
x = 43
m<A = 3x + 6 = 3(43) + 6 = 135
Answer: 135 deg
Are you sure this is written correctly. It is not factorable as it is
Answer:
(1,-2)
Step-by-step explanation:
Choose any value for x that is in the domain to plug into the equation.
Choose 0 to substitute in for x to find the ordered pair.
(0, -19/6)
Choose 1 to substitute in for x to find the ordered pair.
Remove parentheses.
y= -19/6 + 7(1)/6
Simplify
y=2
Use the
x and y values to form the ordered pair.
(1,−2)
