Answer: The correct answer is H.
Step-by-step explanation: The correct order of the weights from largest to smallest is shown in choice H. The correct order is 2.25, 2.234, 2.205.
This area is equal to the sum of a circle with a radius of 5/2 in and a rectangle 5 by 15 in so:
A=πr^2+xy
A=π(2.5)^2+5*15
A=6.25π+75 in^2
A≈94.63 in^2 (to nearest hundredth) so
A≈95 in^2 (to nearest whole square inch)
Answer:
-3+x=x+4
Step-by-step explanation:
Pls Mark Brainliest
Answer:
roots : 4, -4, i, -i
Step-by-step explanation:
This gets a bit tricky.
We have to substitude x^2 as u in this problem.
Now to rewrite x^4 − 15x^2 − 16 = 0 with u, we get
u^2 - 15u - 16 = 0
( u - 16) (u + 1)
U = 16
U = -1
<em>This is not the end of the problem. </em>
Now we have to substitute x^2 back to u.
x^2 = 16 --> we get the roots 4 and -4
x^2 = -1 --> we get the roots i and -i
tadah!
Answer:
Equation of midsegment line: y = (-1/4)x + 2.
Step-by-step explanation:
If the parallel sides of a trapezoid are contained by the lines:-
y = (-1/4)x +5 and y = (-1/4)x - 1
Midsegment of any trapezoid is the line segment
1. that is parallel to pair of parallel side of trapezoid and
2. that passes through the middle of the trapezoid and cuts the other two sides into equal-half.
It means the midsegment would have same slope as the parallel lines and y-intercept would be in the middle of intercepts of parallel lines.
So y = mx + b
where m = -1/4 and b = (5 - 1)/2 = 4/2 = 2.
Hence, the equation of midsegment would be y = (-1/4)x + 2.
