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natita [175]
3 years ago
14

What is the equation of the circle?

Mathematics
1 answer:
adoni [48]3 years ago
3 0

Answer:

(x - 3)^2 + (y + 2)^2 = 2^2

Step-by-step explanation:

The center is at x = 3 and y = 2:  (3, 2).  The radius is 2.  Starting with the standard equation of a circle with radius r and center (h, k), we get:

(x - 3)^2 + (y + 2)^2 = 2^2

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\bf \stackrel{h}{34}=100t-16t^2\implies 16t^2-100t+34=0\\\\\\ 8t^2-50t+17=0
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~~~~~~~~~~~~\textit{quadratic formula}
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\stackrel{\stackrel{a}{\downarrow }}{8}t^2\stackrel{\stackrel{b}{\downarrow }}{-50}t\stackrel{\stackrel{c}{\downarrow }}{+17}=0
\qquad \qquad 
t= \cfrac{ -  b \pm \sqrt {  b^2 -4 a c}}{2 a}

\bf t=\cfrac{ - (-50) \pm \sqrt {  (-50)^2 -4(8)(17)}}{2(8)}\implies t=\cfrac{50\pm \sqrt{2500-544}}{16}
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t=\cfrac{50\pm\sqrt{1956}}{16}\implies t=\cfrac{50\pm\sqrt{4\cdot 489}}{16}\implies t=\cfrac{50\pm\sqrt{2^2\cdot 489}}{16}
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\begin{cases}
5.88916805\\
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