To calculate the distance between two points on the coordinate system you have to use the following formula:
![d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%28x_1-x_2%29%5E2%2B%28y_1-y_2%29%5E2%7D)
Where
d represents the distance between both points.
(x₁,y₁) are the coordinates of one of the points.
(x₂,y₂) are the coordinates of the second point.
To determine the length of CD, the first step is to determine the coordinates of both endpoints from the graph
C(2,-1)
D(-1,-2)
Replace the coordinates on the formula using C(2,-1) as (x₁,y₁) and D(-1,-2) as (x₂,y₂)
![\begin{gathered} d_{CD}=\sqrt[]{(2-(-1))^2+((-1)-(-2))}^2 \\ d_{CD}=\sqrt[]{(2+1)^2+(-1+2)^2} \\ d_{CD}=\sqrt[]{3^2+1^2} \\ d_{CD}=\sqrt[]{9+1} \\ d_{CD}=\sqrt[]{10} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20d_%7BCD%7D%3D%5Csqrt%5B%5D%7B%282-%28-1%29%29%5E2%2B%28%28-1%29-%28-2%29%29%7D%5E2%20%5C%5C%20d_%7BCD%7D%3D%5Csqrt%5B%5D%7B%282%2B1%29%5E2%2B%28-1%2B2%29%5E2%7D%20%5C%5C%20d_%7BCD%7D%3D%5Csqrt%5B%5D%7B3%5E2%2B1%5E2%7D%20%5C%5C%20d_%7BCD%7D%3D%5Csqrt%5B%5D%7B9%2B1%7D%20%5C%5C%20d_%7BCD%7D%3D%5Csqrt%5B%5D%7B10%7D%20%5Cend%7Bgathered%7D)
The length of CD is √10 units ≈ 3.16 units
You'd find the vertical asymptotes by seeing where the denominator equals zero; you can do so by factoring the denominator.
In this case, you can factor the denominator into (x+3)(x+2), so if you set each of those equal to zero you can find the equations of the vertical asymptotes (x=-3 and x=-2).
Answer:
A
Step-by-step explanation:
3 x r <u>></u> 34
9514 1404 393
Answer:
B) biker at 12 mph
Step-by-step explanation:
Distance is proportional to time when velocity is constant. It is not constant in the case of stop-and-go traffic, a baseball*, or a slowing car. The speed of the person biking is given as a constant 12 mph, so that person is traveling a distance proportional to time.
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<em>Additional comment</em>
* It depends. The usual assumption is that horizontal speed is constant, in which case the distance from the hitter along the ground is proportional to time. If you are modeling the real world, the ball slows due to air resistance, so distance is not proportional to time.
If you are concerned with the actual distance the baseball travels through the air, the ball's speed slows as it gains height, then increases again as it falls to the ground. The speed is not constant during any part of that travel.
