3 years ago

What relationship between the quantities shown in the table

1 answer:

6 0

I was so in love with this girl I hate the way I loved her I gave her to much love I’m sorry lord I failed you not everyone is ready for me yet ✍

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steposvetlana [31]

The answer would be JG.

If we rotate triangle PMO so that the 6 cm side is on the bottom, it would look more similar to the triangle JGH, and make it clear that side PM corresponds to side JG

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Step-by-step explanation:

when dividing two fractions, you must flip the second fraction over and then multiply

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2 years ago

Which ecpression is equivalent to sqrt 8x^7y^8?

mars1129 [50]

$Domain:\ x\geq0\ \wedge\ y\in\mathbb{R}$

$\sqrt{8x^7y^8}=\sqrt8\cdot\sqrt{x^7}\cdot\sqrt{y^8}=\sqrt{4\cdot2}\cdot\sqrt{x^6\cdot x}\cdot\sqrt{y^{4\cdot2}}\\\\=\sqrt4\cdot\sqrt2\cdot\sqrt{x^6}\cdot\sqrt{x}\cdot\sqrt{(y^4)^2}=2\sqrt2\cdot\sqrt{x^{3\cdot2}}\cdot\sqrt{x}\cdot y^4\\\\=2y^4\sqrt2\cdot\sqrt{(x^3)^2}\cdot\sqrt{x}=2y^4\sqrt{2x}\cdot x^3\\\\=\boxed{2x^3y^4\sqrt{2x}}$

$Used:\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a^2}=a\ for\ a\geq0$

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4 years ago