Part A:
<span>a system of inequalities that only contain points D and E in the overlapping shaded regions is
5y + 2x > 12
2y - x < 12
Part B:
To verify that points D and E are solutions to the system of inequalities, we plug in the coordinate points of points D and E into the system of ineaqualities.
Part C:
</span>To <span>identify the schools that Timothy is allowed to attend we plug in the coordinate values of the points to see which satisfies the inequality y < 3x - 3. Thus Timothy is allowed to attend schools C and F.</span>
Step-by-step explanation:
▲ =1
easy peasy........
Answer: p(x) = a (x-b)(x-c)(x-d)
Step-by-step explanation:
The first step is to determine the degree of the polynomial.
It shall depend totally on the linear factors given for the polynomial.
If there is one, it is a linear polynomial.
If there are 2, then it is a quadratic polynomial.
If there are three then it shall be a cubic polynomial.
Now let us assume that there are three linear factors.
We multiply those factors and write the polynomial.
If x-b, x-c & x-d are the factors we write
p(x) = (x-b)(x-c)(x-d)
But as we may have a leading coefficient so we write the polynomial as
Then we go on to expand this to get the polynomial in the standard form.
Answer:
First option and Fourth option.
Step-by-step explanation:
To solve this exercise you need to use the following Trigonometric Identity:

In this case you know that:

Since triangle ABC is similar to triangle DEF:

Let's begin with the triangle ABC.
You can identify that:

Then, substituing values, you get:

In triangle DEF, you know that:

So, substituing values, you get:

Answer:
The difference between a simple event and a compound event is that.
Event with a single outcome is named as simple event and an event with having two or more than two outcomes is known as compound event.