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Cerrena [4.2K]
3 years ago
8

Find the area of the quadrilateral

Mathematics
1 answer:
Aleks [24]3 years ago
6 0
The area equals 612yds
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Eek help? im a bit confused
Ahat [919]

Answer:

3 3/4

Step-by-step explanation:

Each block is worth 0.5 cm (1/2)

One note - NEVER FORGET THE UNITS

L - 5 blocks (5 blocks × 0.5cm = 2.5cm)

W - 2 blocks (2 blocks × 0.5cm = 1cm)

H - 3 blocks (3 blocks × 0.5cm = 1.5cm)

Formula for Volume:

V = L × W × H

V = 2.5cm × 1cm × 1.5cm = 3.75cm (fraction can be 3 3/4)

You're welcome :)

6 0
2 years ago
Read 2 more answers
Solve 1/5x+3=10. Show all work and check it
iren2701 [21]
1/5x + 3 = 10

Subtract by 3 on both sides. 

1/5x = 7.

Now to isolate the variable, flip the coefficient in front of the variable and multiply both sides by it. 

5(1/5x) = 7(5)

x = 7(5)
x = 35

Now to check:

1/5(35) + 3 = 10

35/5 + 3 = 10

35/5 is 7.

7 + 3 = 10

10 = 10
5 0
3 years ago
Read 2 more answers
Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and st
SashulF [63]

Answer:

0.7233

Step-by-step explanation:

We want to find the area between the z-scores z=-0.95 and z=1.25.

We first find the area to the left of each z-score, and subtract the smaller area from the bigger one.

For the area to the left of z=-0.95, we read -0.9 under 5 from the standard normal distribution table.

This gives P(z<-0.95)=0.1711

Similarly the area to the left of z=1.25 is

P(z<1.25)=0.8944

Now the area between the two z-scores is

P(-0.25<z<1.25)=0.8944-0.1711=0.7233

7 0
3 years ago
Gravel is being dumped from a conveyor belt at a rate of 20 ft3 /min and its coarseness is such that it forms a pile in the shap
pantera1 [17]

Answer:

The height of the pile is increasing at the rate of  \mathbf{ \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

Step-by-step explanation:

Given that :

Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min

i.e \dfrac{dV}{dt}= 20 \ ft^3/min

we know that radius r is always twice the   diameter d

i.e d = 2r

Given that :

the shape of a cone whose base diameter and height are always equal.

then d = h = 2r

h = 2r

r = h/2

The volume of a cone can be given by the formula:

V = \dfrac{\pi r^2 h}{3}

V = \dfrac{\pi (h/2)^2 h}{3}

V = \dfrac{1}{12} \pi h^3

V = \dfrac{ \pi h^3}{12}

Taking the differentiation of volume V with respect to time t; we have:

\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}

\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}

we know that:

\dfrac{dV}{dt}= 20 \ ft^3/min

So;we have:

20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}

20= 56.25 \pi \times \dfrac{dh}{dt}

\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

The height of the pile is increasing at the rate of  \mathbf{ \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

8 0
3 years ago
Can someone help me plz and thank u
alexandr402 [8]

Answer:

<A = 44

Step-by-step explanation:

A triangle is 180 degrees

(x+59) + (x+51) + 84 = 180        >> add everything on the left side

2x + 194 = 180                          >> subtract both sides by 194

2x = -14                                     >> divide both sides by 2 to get x alone

x = -7

since you are finding A<, substitute

<A = x + 51

<A = (-7) + 51

<A = 44  

3 0
3 years ago
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