Question:
At noon a tank contains 6 cm of water after several hours it contains 3 cm of water what is the percent decrease of water in the tank
Answer:
The percent Decrease of water in the tank is 50%
Step-by-step explanation:
Given:
Initial amount of water in the tank at the noon = 6 cm
amount of water remained in water after several hours = 3 cm
To Find:
The percent decrease =?
Solution:
The percent decrease in the tank
=>
Substituting the values
=>
=>
=>
=> 50
Answer:
Siobhan makes $9.18 per hour.
Step-by-step explanation:
9*20% is 1.8 so add that to 9 to get 10.80 then times 10.80 by 15% to get 1.62 so you subtract 1.62 from 10.80 to get $9.18
Answer:
f(4) =0 because 4>0
f(-2) =-2 coz -2 lies between 0 and -3
f(-5) =2/-5
C strong
Shshsjshshasjajasja
Answer:
It does not matter whether you multiply the radicands or simplify each radical first. You multiply radical expressions that contain variables in the same manner. As long as the roots of the radical expressions are the same, you can use the Product Raised to a Power Rule to multiply and simplify.
Step-by-step explanation:
