3 years ago

Write -2i + (9 - 3i) - (6 - 10i) as a complex number in standard form.

1 answer:

4 0

Answer:

3 + 5i

Step-by-step explanation:

-2i + (9 - 3i) - (6 - 10i) = -2i + 9 - 3i -6 + 10i

= -2i - 3i +10i + 9 - 6 = 3 + 5i

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I am Lyosha [343]

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malfutka [58]

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ehidna [41]

$a=00110111 = 00110_2 \times 2^{111_2} = 6 \times 2^{-1} = 3$

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Hard to select the correct answers without seeing the choices. Let's check a couple,

$11111001 = -(00000+1) \times 2^{1} = -2 \quad\checkmark$

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irakobra [83]

It will come out to a flat number like 10 20 30 40 ect and the counterfeit will have a 1 at the end such as 11 21 31 41.
Hope i Helped

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