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ankoles [38]
3 years ago
10

Write -2i + (9 - 3i) - (6 - 10i) as a complex number in standard form.

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
4 0

Answer:

3 + 5i

Step-by-step explanation:

-2i + (9 - 3i) - (6 - 10i) = -2i + 9 - 3i -6 + 10i

                    = -2i - 3i +10i + 9 - 6 = 3 + 5i

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Answer:

-\frac{1}{12}

Step-by-step explanation:

So we have the expression:

\frac{2}{6}-\frac{5}{12}

To subtract, we want to have a common denominator. So, let's find a common denominator by using the LCM.

The LCM of 6 and 12 is 12.

Since the second term is already 12, let's multiply the first term by 2 to get its denominator to be 12:

=(\frac{2}{2})\frac{2}{6}-\frac{5}{12}

Multiply:

=\frac{4}{12}-\frac{5}{12}

Now, we can combine the fractions:

=\frac{4-5}{12}

Subtract:

=\frac{-1}{12}

And we are done!

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