The equation would be like this:
Hoped I helped
Y=3x-10 and 3x+2y=16
y=3x-10
subsitute 3x-10 for y in other equation
3x+2y=16
3x+2(3x-10)=16
distribute
3x+6x-20=16
9x-20=16
add 20 both sides
9x=36
divide both sides by 9
x=4
sub back
y=3x-10
y=3(4)-10
y=12-10
y=2
x=4
y=2
(4,2) is soluiton
Answer:
Part A: chosen method is by factoring
Part B: First rewrite the equation by writing -24 as a difference so you get x² -9x - 15x + 135 = 0. Then factor out the x and the -15 from the equation so you get x(x-9) - 15(x-9) = 0. Then factor out x-9 from the equation so you have (x-9)(x-15) = 0. Finally, set each expression to 0: x-9=0 and x-15=0 and then solve: x=9 and x=15
Part C: x=9, x=15