All categories

3 years ago

!!!! HELP PLEASE !!!! WILL GIVE BRAINLIEST!!!!!!!!!

Mathematics

1 answer:

AnnyKZ [126]3 years ago

6 0

Answer:

Step 1 is incorrect because it was mutiplied. Instead, you should divide.

Step-by-step explanation:

You might be interested in

Year 9 Maths - linear equations please help

jek_recluse [69]

Answer:

x=1 & y=6 or (1,6)

Step-by-step explanation:

3x-x+5=7 Substitute the 2nd equation in for y

2x+5=7 Do 3x-x to get 2x

2x=2 Subtract 5 from both sides

x=1 Divide 2 from both sides

y=1+5 Insert 1 as x

y=6 Add 1+5 to solve for y

Hope this helped!

3 0

3 years ago

Read 2 more answers

A line passing through the points (6, –2) and (–2, 4). Complete the work shown: 1. Use slope formula to find the slope. 2. Subst

Dennis_Churaev [7]

Answer:

2.5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Mr. Smith borrows $9000.00 from the bank at 6% per annum simple interest. . The loan is to be repaid in 4 years. What will be th

bezimeni [28]

Answer:

21323

Step-by-step explanation:

6 0

3 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago

What is 334.54 + 198 grams

lidiya [134]

334.54 + 198 = 532.54 grams total

hope this helps

6 0

3 years ago

Read 2 more answers