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2 years ago

Soo Lin walks her dog at a constant rate. The distance

Mathematics

1 answer:

Vilka [71]2 years ago

8 0

Answer:(1) The distance Soo Lin walks is a function of time = True

(2) The time it takes soo- in to walk a certain distance is a function of distance = False

Step-by-step explanation:

Since the distance walked, e in miles= 3.17t

Where t is time

From the equation,

time t is an independent variable, it does not dependent on distance e

Also

distance e is a dependent variable that depend on time t

Therefore,

Distance e is a function of time t.

While time t is not a function of distance e.

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What number has factors that add up to thirty

NNADVOKAT [17]

29 = 1 * 29
1 + 29 = 30
thus answer is 29

5 0

3 years ago

F is between E and G, EF=2x-2, EG=6x+10, and FG=6x. Find x.

BartSMP [9]

Answer:

x = 6

Step-by-step explanation:

Given that F is between E and G , then

EF + FG = EG , substitute values

2x - 2 + 6x = 6x + 10 , that is

8x - 2 = 6x + 10 ( subtract 6x from both sides )

2x - 2 = 10 ( add 2 to both sides )

2x = 12 ( divide both sides by 2 )

x = 6

4 0

3 years ago

The side of a square are 3 cm long. One vertex of the square is at (2,0) on a square coordinate grid marked in centimeters units

yuradex [85]

(2,0) (5.0) (5,3) (2,3)
(2,0) (-1,0) (2,3) (-1,3)

3 0

3 years ago

In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.

vodka [1.7K]

Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.

Solution:

Given that,

Total circulation of local newspaper in 2000 = 3250

Total circulation of local newspaper in 2001 = 3640

Total circulation of local newspaper in 2002 = 4100

Finding percent of increase in the newspaper’s circulation from 2000 to 2001:

$\text { Percent increase from } 2000 \text { to } 2001=\frac{\text { change in circulation from 2001 - 2000 }}{\text { circulation in } 2000} \times 100$

$\begin{array}{l}{=\frac{3640-3250}{3250} \times 100} \\\\ {=\frac{390}{3250} \times 100=12 \%}\end{array}$

Finding percent of increase in the newspaper’s circulation from 2001 to 2002:

$\begin{array}{l}{\text { Percent increase from } 2001 \text { to } 2002=\frac{\text { change in circulation }}{\text {circulation in } 2001} \times 100} \\\\ {=\frac{4100-3640}{3640} \times 100} \\\\ {=\frac{460}{3640} \times 100=12.6 \%}\end{array}$

As we can see 12% < 12.6%

So period of 2001 to 2002 has higher increase percentage.

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2 years ago

13 of the 18 players on the varsity soccer team are seniors. What percent of the players on the team are not seniors?

irakobra [83]

.9% of the players are not seniors

6 0

2 years ago