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3 years ago

What's the correct choice?

Mathematics

1 answer:

IRISSAK [1]3 years ago

3 0

What's the correct choice? To choose or not to choose. Just RNG

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Will be giving out brainliest to whoever can answer this first

wariber [46]

Answer:

angle BOD = angle AOC

( cuz they are vertical opposite angles )

so angle BOD = 65°

8 0

3 years ago

How do i find the perimeter?

Arada [10]

Answer: 8x+12

Step-by-step explanation:

perimeter equals (x+4) + (3x+2) + (x+4) + (3x+2) = x+4 + 3x+2 + x+4 + 3x+2 = 8x+12

8 0

3 years ago

Read 2 more answers

What are factors of 36 that add up to 0

Damm [24]

X^2+ox-36=(x-6)(x+6)
x^2+0x-36=0

3 0

3 years ago

Can y’all help me pls

krok68 [10]

Answer:

2. The change in expected height for every one additional centimeter of femur length.

Step-by-step explanation:

1. The expected height for someone with a femur length of 65 centimeters.

Doesn't make sense, that would be height value when centimeters = 65.

2. The change in expected height for every one additional centimeter of femur length.

Makes sense, for every increase in one additional centimeter, we can expect the height to be proportional to the slope.

3. The femur length for someone with an expected height of 2.5 centimeters.

Doesn't make sense, the linear relationship relies on the femur length to get the height.

4. The change in expected femur length for every one additional centimeter of height.

Doesn't make sense, again, the linear relationship relies on the femur length.

6 0

2 years ago

Determine which of the sets of vectors is linearly independent. A: The set where p1(t) = 1, p2(t) = t2, p3(t) = 3 + 3t B: The se

defon

Answer:

The set of vectors A and C are linearly independent.

Step-by-step explanation:

A set of vector is linearly independent if and only if the linear combination of these vector can only be equalised to zero only if all coefficients are zeroes. Let is evaluate each set algraically:

$p_{1}(t) = 1$ , $p_{2}(t)= t^{2}$ and $p_{3}(t) = 3 + 3\cdot t$ :

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (3 +3\cdot t) = 0$

$(\alpha_{1}+3\cdot \alpha_{3})\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot t = 0$

The following system of linear equations is obtained:

$\alpha_{1} + 3\cdot \alpha_{3} = 0$

$\alpha_{2} = 0$

$\alpha_{3} = 0$

Whose solution is $\alpha_{1} = \alpha_{2} = \alpha_{3} = 0$ , which means that the set of vectors is linearly independent.

$p_{1}(t) = t$ , $p_{2}(t) = t^{2}$ and $p_{3}(t) = 2\cdot t + 3\cdot t^{2}$

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot t + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (2\cdot t + 3\cdot t^{2})=0$

$(\alpha_{1}+2\cdot \alpha_{3})\cdot t + (\alpha_{2}+3\cdot \alpha_{3})\cdot t^{2} = 0$

The following system of linear equations is obtained:

$\alpha_{1}+2\cdot \alpha_{3} = 0$

$\alpha_{2}+3\cdot \alpha_{3} = 0$

Since the number of variables is greater than the number of equations, let suppose that $\alpha_{3} = k$ , where $k\in\mathbb{R}$ . Then, the following relationships are consequently found: