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vichka [17]
2 years ago
9

Can y’all help me pls

Mathematics
1 answer:
krok68 [10]2 years ago
6 0

Answer:

2. The change in expected height for every one additional centimeter of femur length.

Step-by-step explanation:

<u>1. The expected height for someone with a femur length of 65 centimeters.</u>

<em>Doesn't make sense, that would be height value when centimeters = 65.</em>

<u>2</u><u><em>. </em></u><u>The change in expected height for every one additional centimeter of femur length.</u>

<em>Makes sense, for every increase in one additional centimeter, we can expect the height to be proportional to the slope.</em>

<u>3. The femur length for someone with an expected height of 2.5 centimeters.</u>

<em>Doesn't make sense, the linear relationship relies on the femur length to get the height.</em>

<u>4. The change in expected femur length for every one additional centimeter of height.</u>

<em>Doesn't make sense, again, the linear relationship relies on the femur length.</em>

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(ar^b)^4=81r^24<br> where a and b are positive integers. <br> Work out a and b
galina1969 [7]

Answer:

Vales of a =3 and b = 6

Step-by-step explanation:

Given that: (ar^b)^4 = 81r^{24}            .....[1] where a and b are positive integers

we can write 81 and 24 as;

81 = 3 \cdot 3 \cdot 3 \cdot 3 = 3^4

24 = 4 \cdot 6

We have [1] as;

(ar^b)^4 = 3^4r^{4 \cdot 6}

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4 years ago
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