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2 years ago

The product of 7,x, and y is represented by the expression 7xy. If the value of x is negative, what

Mathematics

2 answers:

Sergio [31]2 years ago

8 0

Answer:

it must be negative

Step-by-step explanation:

7xy = a positive number

7 is positive.

x is a negative number.

y must be negative for 7xy to be positive.

(+) * (-) * (-) = +

The product of two negative numbers is positive.

Sphinxa [80]2 years ago

5 0

Answer:

In the expression of 7xy, if x is negative, then y must also be negative for the product to be positive.

Let me know if this helps!

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5/6 divided by 1 and 1/2?

Tema [17]

Answer:

5/9

Step-by-step explanation:

(5/6)/1 1/2

5/9

Merry Christmas

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3 years ago

Can someone help me with this?

Natalija [7]

use the Pythagoras theorem method

a squared plus b squared equals c square

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3 years ago

Solve - 2x - 7 > X+ 8. O A. x<-3 O B. x<-5 O C. x>-5 O D. x>-3

Rzqust [24]

Answer:

x < -5

Step-by-step explanation:

- 2x - 7 > x+ 8

Add 2x to each side

- 2x+2x - 7 > x+2x+ 8

-7 > 3x+8

Subtract 8 from each side

-7-8 > 3x+8-8

-15 > 3x

Divide by 3

-15/3 > 3x/3

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x < -5

6 0

2 years ago

A bicycle store costs $2250 per month to operate. The store pays an average of $40 per bike. The average selling price of each

lesantik [10]

Answer:

Step-by-step explanation:

Given That :

Operation cost = $2250 per month

Purchase price per bike = $40

Average selling price per bike = $70

How many bicycles must the store sell each month to break even ;

Break even point = point at which there is net profit / loss = 0

Let number of bicycles store must sell = x

Operation cost + (purchase price * Number of bicycles) = selling price * Number of bicycles

2250 + 40x = 70x

2250 = 70x - 40x

2250 = 30x

x = 2250 / 30

x = 75

To break even 75 bicycles must be sold

5 0

2 years ago

Simplify 1+sinx/cosx+cosx/1+sinx

Dmitry [639]

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$\frac{1 + 2sin(x) + sin^{2}(x)}{cos(x)[1 + sin(x)]} + \frac{cos^{2}(x)}{cos(x)[1 + sin(x)]}$
$\frac{1 + 2sin(x) + sin^{2}(x) + cos^{2}(x)}{cos(x)[1 + sin(x)]}$
$\frac{1 + 2sin(x) + 1}{cos(x)[1 + sin(x)]}$
$\frac{1 + 1 + 2sin(x)}{cos(x)[1 + sin(x)]}$
$\frac{2 + 2sin(x)}{cos(x)[1 + sin(x)]}$
$\frac{2[1 + sin(x)]}{cos(x)[1 + sin(x)]}$
$\frac{2}{cos(x)}$
$2sec(x)$

6 0

2 years ago