Answer:
Use the quadratic formula
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
5
2
−
4
1
+
8
=
0
5x^{2}-41x+8=0
5x2−41x+8=0
=
5
a={\color{#c92786}{5}}
a=5
=
−
4
1
b={\color{#e8710a}{-41}}
b=−41
=
8
c={\color{#129eaf}{8}}
c=8
=
−
(
−
4
1
)
±
(
−
4
1
)
2
−
4
⋅
5
⋅
8
√
2
⋅
5
2
Simplify
3
Separate the equations
4
Solve
Solution
=
8
=
1
5
Answer: The simplified version of this is 14d²c³√66
Step-by-step explanation:
Not sure about this but, is it a line?
System: x + y = 44; x = 2y + 2
Solve with substitution: x = 30; y = 14
x + y = 44
x = 2y + 2
Substitute 2y + 2 for x
2y + 2 + y = 44
3y + 2 = 44
Subtract 2 on both sides.
3y = 42
y = 14
Now substitute back in.
x + 14 = 44
Subtract 14 on both sides.
x = 30
