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3 years ago

Make a inequality

1 answer:

7 0

To finish in 5 weeks:
For 4 of those weeks, read 4 chapters per week. On one of the weeks read 3 chapters.

To finish in 4 weeks:
For 3 of those weeks, read 5 chapters per week. On one of the weeks read 4 chapters.

To finish in 3 weeks:
For 2 of those weeks, read 6 chapters per week. On one of the weeks read 7 chapters.

To finish in 2 weeks:
On one week read 10 chapters. On the other week read 9 chapters.

To finish in 7 days:
For 6 of those days, read 3 chapters. On one of the days, read 1 chapter.

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What is 503 rounded to the nearest hundred

yawa3891 [41]

500 is the answer because 500 is much closer

3 0

3 years ago

What is the perimeter of the garage if d=3<br><br> I’m marking branliest

mart [117]

Answer:

perimeter= 46

Step-by-step explanation:

(3(3)-2) + (3(3)-2) + (5(3)+1) + (5(3)+1)

7 + 7 + 16 + 16

= 46

5 0

3 years ago

Questions attached as screenshot below:Please help me I need good explanations before final testI pay attention

Nikitich [7]

The acceleration of the particle is given by the formula mentioned below:

$a=\frac{d^2s}{dt^2}$

Differentiate the position vector with respect to t.

$\begin{gathered} \frac{ds(t)}{dt}=\frac{d}{dt}\sqrt[]{\mleft(t^3+1\mright)} \\ =-\frac{1}{2}(t^3+1)^{-\frac{1}{2}}\times3t^2 \\ =\frac{3}{2}\frac{t^2}{\sqrt{(t^3+1)}} \end{gathered}$

Differentiate both sides of the obtained equation with respect to t.

$\begin{gathered} \frac{d^2s(t)}{dx^2}=\frac{3}{2}(\frac{2t}{\sqrt[]{(t^3+1)}}+t^2(-\frac{3}{2})\times\frac{1}{(t^3+1)^{\frac{3}{2}}}) \\ =\frac{3t}{\sqrt[]{(t^3+1)}}-\frac{9}{4}\frac{t^2}{(t^3+1)^{\frac{3}{2}}} \end{gathered}$

Substitute t=2 in the above equation to obtain the acceleration of the particle at 2 seconds.

$\begin{gathered} a(t=1)=\frac{3}{\sqrt[]{2}}-\frac{9}{4\times2^{\frac{3}{2}}} \\ =1.32ft/sec^2 \end{gathered}$

The initial position is obtained at t=0. Substitute t=0 in the given position function.

$\begin{gathered} s(0)=-23\times0+65 \\ =65 \end{gathered}$

8 0

1 year ago

If EF = 5w + 20, FG = 7w + 28, and EG = 72, find the value of w. Find EF and FG

IrinaK [193]

Answer:

w = 2, EF = 30 , FG = 42

Explanation:

We have EF = 5w + 20 and FG = 7w + 28

Since these points E, F and G are col-linear points we have.

EG = EF + FG

And given that EG = 72

So, EF+EG = 72

5w + 20 + 7w + 28 = 72

12w + 48 = 72

12 w = 24

w = 2

So EF = 5w + 20 = 5x2 + 20 = 30

FG = 7w + 28 = 7x2 + 28 = 42

7 0

3 years ago

Help pleaseeeeee nowwwwww

Snezhnost [94]

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below :)

5 0

3 years ago