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barxatty [35]
3 years ago
12

Make a inequality

Mathematics
1 answer:
liraira [26]3 years ago
7 0
To finish in 5 weeks:
For 4 of those weeks, read 4 chapters per week. On one of the weeks read 3 chapters.

To finish in 4 weeks:
For 3 of those weeks, read 5 chapters per week. On one of the weeks read 4 chapters.

To finish in 3 weeks:
For 2 of those weeks, read 6 chapters per week. On one of the weeks read 7 chapters.

To finish in 2 weeks:
On one week read 10 chapters. On the other week read 9 chapters.

To finish in 7 days:
For 6 of those days, read 3 chapters. On one of the days, read 1 chapter.
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*PLEASE ANSWER ASAP* John is playing a game with two friends. Using the spinner pictured, one friend spun a three, and the other
levacccp [35]

Answer:

3

Step-by-step explanation:

he wants a 6,7,or8

5 0
3 years ago
How can i prove this property to be true for all values of n, using mathematical induction.
chubhunter [2.5K]

Proof -

So, in the first part we'll verify by taking n = 1.

\implies \: 1  =  {1}^{2}  =  \frac{1(1 + 1)(2 + 1)}{6}

\implies{ \frac{1(2)(3)}{6} }

\implies{ 1}

Therefore, it is true for the first part.

In the second part we will assume that,

\: {  {1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  =  \frac{k(k + 1)(2k + 1)}{6}  }

and we will prove that,

\sf{ \: { {1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  + (k + 1)^{2} =  \frac{(k + 1)(k + 1 + 1) \{2(k + 1) + 1\}}{6}}}

\: {{1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  + (k + 1)^{2}  =  \frac{(k + 1)(k + 2) (2k + 3)}{6}}

{1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  + (k + 1)^{2} = \frac{k (k + 1) (2k + 1) }{6} +  \frac{(k + 1) ^{2} }{6}

{1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  + (k + 1)^{2} = \frac{k(k+1)(2k+1)+6(k+1)^ 2 }{6}

{1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  + (k + 1)^{2} = \frac{(k+1)\{k(2k+1)+6(k+1)\} }{6}

{1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  + (k + 1)^{2} = \frac{(k+1)(2k^2 +k+6k+6) }{6}

{1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  + (k + 1)^{2} = \frac{(k+1)(2k^2+7k+6) }{6}

{1}^{2} +  {2}^{2}  +  {3}^{2}  + ..... +  {k}^{2}  + (k + 1)^{2} = \frac{(k+1)(k+2)(2k+3) }{6}

<u>Henceforth, by </u><u>using </u><u>the </u><u>principle </u><u>of </u><u> mathematical induction 1²+2² +3²+....+n² = n(n+1)(2n+1)/ 6 for all positive integers n</u>.

_______________________________

<em>Please scroll left - right to view the full solution.</em>

8 0
2 years ago
I need help with #14
kodGreya [7K]
35 brownies were brought to class by Lauren
7 0
3 years ago
What is the value of a in the equation a = 2 + 3a + 6?
gulaghasi [49]
A = 2+3a +6

a-3a = 8

-2a = 8

a = -8/2 = -4
3 0
3 years ago
The diameter of a semicircle is 8 miles. What is the semicircle's perimeter? Use 3.14 for ​.
wlad13 [49]

Answer:

41.13 cm

Step-by-step explanation:

ITSSSS RIGHTTTTTTTTT

7 0
3 years ago
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