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Dahasolnce [82]
3 years ago
11

Help with photo plz .....how do i do this?

Mathematics
1 answer:
UkoKoshka [18]3 years ago
7 0
Either use a graphing calculator or substitute the  value of x for x
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Pls ANSWERRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
natta225 [31]

Hi there!

\large\boxed{ 9.4m}

Find the perimeter using the formula:

P = 2l + 2w

It is given that the dimensions are 2.8 × 1.9 so plug these number into the equation:

P = 2(2.8) + 2(1.9)

P = 5.6 + 3.8

P = 9.4m

4 0
3 years ago
Write a real word problem that involves finding the product of 3/4 and 1/8
jekas [21]
A carpenter wants you to find the surface area of a shelf top. The length of the shelf is 3/4 m and the depth is 1/8 m.
8 0
3 years ago
Check my work? I came up with 60 degrees. Let me know!
dalvyx [7]
90 minus 32 is 58! You were off by two degrees:)
3 0
3 years ago
Read 2 more answers
9.4.15
Brilliant_brown [7]

Answer:

250

Step-by-step explanation:

mulitply 28.95 by 4 to get that out of the way, this equals 115.

subtract: 200-115=85

divide: 85/.34

answer:250

3 0
3 years ago
Read 2 more answers
A cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. The material for the sides of the can costs
LenKa [72]

Answer:

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

Step-by-step explanation:

Volume of the Cylinder=400 cm³

Volume of a Cylinder=πr²h

Therefore: πr²h=400

h=\frac{400}{\pi r^2}

Total Surface Area of a Cylinder=2πr²+2πrh

Cost of the materials for the Top and Bottom=0.06 cents per square centimeter

Cost of the materials for the sides=0.03 cents per square centimeter

Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)

C=0.12πr²+0.06πrh

Recall: h=\frac{400}{\pi r^2}

Therefore:

C(r)=0.12\pi r^2+0.06 \pi r(\frac{400}{\pi r^2})

C(r)=0.12\pi r^2+\frac{24}{r}

C(r)=\frac{0.12\pi r^3+24}{r}

The minimum cost occurs when the derivative of the Cost =0.

C^{'}(r)=\frac{6\pi r^3-600}{25r^2}

6\pi r^3-600=0

6\pi r^3=600

\pi r^3=100

r^3=\frac{100}{\pi}

r^3=31.83

r=3.17 cm

Recall that:

h=\frac{400}{\pi r^2}

h=\frac{400}{\pi *3.17^2}

h=12.67cm

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

3 0
3 years ago
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