Question

Solve the simultaneous equations2x + 5y + 11 = 03x - y-8= 0​

Answer 1

Answer:

x = 1$\frac{12}{17}$, y = -2$\frac{15}{17}$

Step-by-step explanation:

2x + 5y + 11 = 0 --- Equation 1

3x - y - 8 = 0

15x - 5y - 40 = 0 --- Equation 2

Equations 1+2: 2x + 5y + 11 + 15x - 5y - 40 = 0 + 0

17x - 29 = 0

17x = 29

x = 29 ÷ 17

x = 1$\frac{12}{17}$

Substitute x = 1$\frac{12}{17}$ into Equation 1:

2x + 5y + 11 = 0

2(1$\frac{12}{17}$) + 5y + 11 = 0

3$\frac{7}{17}$ + 5y = -11

5y = -11 - 3$\frac{7}{17}$

    = -14$\frac{7}{17}$

y = -14$\frac{7}{17}$ ÷ 5

y = -2$\frac{15}{17}$