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fiasKO [112]
2 years ago
9

Solve the simultaneous equations2x + 5y + 11 = 03x - y-8= 0​

Mathematics
1 answer:
vlabodo [156]2 years ago
5 0

Answer:

x = 1\frac{12}{17}, y = -2\frac{15}{17}

Step-by-step explanation:

2x + 5y + 11 = 0 --- Equation 1

3x - y - 8 = 0

15x - 5y - 40 = 0 --- Equation 2

Equations 1+2: 2x + 5y + 11 + 15x - 5y - 40 = 0 + 0

17x - 29 = 0

17x = 29

x = 29 ÷ 17

x = 1\frac{12}{17}

Substitute x = 1\frac{12}{17} into Equation 1:

2x + 5y + 11 = 0

2(1\frac{12}{17}) + 5y + 11 = 0

3\frac{7}{17} + 5y = -11

5y = -11 - 3\frac{7}{17}

    = -14\frac{7}{17}

y = -14\frac{7}{17} ÷ 5

y = -2\frac{15}{17}

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