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Roman55 [17]
2 years ago
14

The graph of is shown below. What is the value of y when x = 0?

Mathematics
2 answers:
Mekhanik [1.2K]2 years ago
7 0

The value of y when x = 0 is -2 and -2 is the y-intercept of the mod function option (D) -2 is correct.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

It is given that:

The mod function:

y = |x| - 2

The graph of the mod function is shown in the picture.

As we know when x = 0 the graph crosses the y-axis and it is known as y-intercept,

Plug x = 0 in the above equation:

y = |0| - 2

y = -2

Thus, the value of y when x = 0 is -2 and -2 is the y-intercept of the mod function option (D) -2 is correct.

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

jarptica [38.1K]2 years ago
6 0

\huge\text{Hey there!}


\huge\textsf{This equation/question should be easy to}\\\\\huge\textsf{to solve for because, we have everything you}\\\\\huge\textsf{you will need on your graph and somewhat in}\\\\\huge\textsf{the question because it already gave you the}\\\\\huge\boxed{\mathsf{x-intercept}}\huge\textsf{.}
\mathsf{y = |x| - 2}

\mathsf{y = |0| - 2}

\mathsf{y = 0 - 2}

\mathsf{y = -2}
\huge\textsf{Therefore, your answer should be: }

\huge\boxed{\mathsf{y= }\frak{\ -2} \ \rm{(Option\ D.)}}\huge\checkmark


\huge\text{Good luck on your assignment \& enjoy your day!}

<h3>
~\frak{Amphitrite1040:)}</h3>
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Write an equation for this relationship.
disa [49]

Answer:

y=18.5x

Step-by-step explanation:

74-55.5=18.50

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111-92.5=18.50

(3,55.50)

y=18.5x +b

55.50=18.5(3)+b

55.50=55.50+b

b=0

8 0
3 years ago
Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm
GuDViN [60]
Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones). 

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

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5 0
3 years ago
Help me please I’m going INSANE
Ksivusya [100]

Answer:

24/4

Step-by-step explanation:

all you have to do is multiply 4x6=24

7 0
3 years ago
Read 2 more answers
Solve for t<br><br> 4/3 = t/7
Mumz [18]

Answer:

\frac{28}{3}=t

Step-by-step explanation:

\frac{4}{3}=\frac{t}{7}

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(4)(7) = (3)(t)

Simplify,

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Inverse operations,

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2 years ago
How to divide (x^2+5x-36)÷(x-4)
mr_godi [17]

Answer:

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Step-by-step explanation:

Since the divisor is in the form of <em>x - c</em>, use what is called <em>Synthetic Division</em>. Remember, in this formula, -c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:

4| 1 5 -36

↓ 4 36

----------------

1 9 0 → x + 9

You start by placing the c in the top left corner, then list all the coefficients of your dividend [x² + 5x - 36]. You bring down the original term closest to <em>c</em><em>,</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have NO REMAINDER. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x, and the 9 follows right behind it, giving you the other factor of x + 9.

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

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