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djyliett [7]
3 years ago
15

Suppose that Dr. Vergara makes a free throw with probability 0.8 and, independently, Dr. Agor makes a free throw with probabilit

y 0.4. They each attempt one free throw. (a) Given that only one of them made a free throw, what is the probability that Dr. Agor made his free throw
Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
7 0

Answer:

40%

Step-by-step explanation:

adelina 88 [10]3 years ago
5 0

Answer:

The probability that Dr. Agor made his free throw is 40%.

Step-by-step explanation:

Given the fact that Dr. Agor usually converts his free throws with a probability of 0.4, to determine the percentage of probability that he will convert his free throw, the following calculation has to be performed:

0.4 x 100 x 1 = X

40 x 1 = X

40 = X

Therefore, Dr. Agor has a 40% chance of making his free throw.

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-The ordered pair (-1, 5) is a solution to the first equation because it makes the first equation true.

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Step-by-step explanation:

<u><em>The correct question is</em></u>

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step 1

<u><em>Verify if the ordered pair satisfy  the first equation </em></u>

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The ordered pair satisfy the first equation

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step 2

<u><em>Verify if the ordered pair satisfy  the second equation </em></u>

Substitute the values of x and y of the ordered pair in the second equation  

For x=-1, y=5    

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<em>The ordered pair is a solution to the second equation because it makes the second  equation true</em>

therefore

<em>The ordered pair (-1, 5) is a solution to the system because it makes both equations true</em>

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