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timama [110]
1 year ago
10

Find the inequality represented in the graph.

Mathematics
1 answer:
Digiron [165]1 year ago
7 0

Answer: y > -1/2x + 2

Step-by-step explanation: first, in order to find the inequalities you should find the gradient by choosing two points from the line and you should you the formula m=y2-y1/x2-x1 to find the gradient.

Next, you should find the y-intercept in order to complete the inequality it can be easily found as the y-intercept is the place where the line crosses the y axis

Then you create your equation { y = -1/2x + 2 } and then if above the line is shaded then it is {> greater than} and if below the line is shaded then it should be {< less than}

(so you should replace the equation with the lesser or greater sign according to the way the graph is shaded)

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A city has 5 new houses for every 7 old houses. If there are 45 new houses in the city, how many old houses are there?
torisob [31]

Answer:

63

Step-by-step explanation:

Make a ratio:

5 : 7 = 45 : x

x = 63

6 0
3 years ago
What is total number of elements in 3 trials of rolling a 6-sided die?
umka21 [38]
The answers should be 9
6 0
3 years ago
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Nonamiya [84]

Answer:

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Step-by-step explanation:

6 0
2 years ago
Venus Waldo reviewed her account statement and wanted to verify that the interest amount was correct. Her new balance was $12,09
user100 [1]

Answer:

The interest on the savings account is $46.47

Step-by-step explanation:

Here, we want to know the interest earned on the savings account.

The difference between the new and previous balance will be; 12,098.12 - 9,053.20 = $3,044.92

The difference between amount deposited and amount withdrawn is 3,298.45 - 300 = 2,998.45

This is the amount that is supposed to be on the account without interest

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3 0
3 years ago
Somebody please help with this problem
Mrrafil [7]

Step-by-step explanation:

We have been given that AE=BE and \angle1\cong \angle2.

We can see that angle CEA is vertical angle of angle DEB, therefore, m\angle CEA=m\angle DEB as vertical angles are congruent.

We can see in triangles CEA and DEF that two angles and included sides are congruent.

\angle 1\cong \angle 2

AE=BE

\angle CEA\cong\angle DEB or \angle 3\cong \angle 4  

Therefore, \Delta CEA\cong \Delta DEB by ASA postulate.

Since corresponding parts of congruent triangles are congruent, therefore CE must be congruent to DE.

5 0
3 years ago
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