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olga55 [171]
3 years ago
8

6. Mrs. Sam buys pencils for $15 per one hundred packs.

Mathematics
1 answer:
Alexxx [7]3 years ago
4 0

Answer:

a.) her loss is 5 dollars

b.) her profit is 10 dollars

c.) she should sell them for $0.15

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Find the solutions to x⁴-5x²-36=0 and the x-intercepts of the graph of y=x⁴-5x²-36.
disa [49]

Answer:

The solutions x^4-5x^2-36=0 are x=3,\:x=-3,\:x=2i,\:x=-2i and the x-intercepts of y=x^4-5x^2-36 are x=3,\:x=-3

Step-by-step explanation:

Finding the solutions to x^4-5x^2-36 means finding the roots, a root is where the function is equal to zero.

The x-intercept is the point at which the graph crosses the x-axis. At this point, the y-coordinate is zero.

To find the roots you need to:

Rewrite the equation with u=x^2 and u^2=x^4

u^2-5u-36=0

Solve by factoring

\mathrm{Break\:the\:expression\:into\:groups}\\u^2-5u-36=\left(u^2+4u\right)+\left(-9u-36\right)

\mathrm{Factor\:out\:}u\mathrm{\:from\:}u^2+4u=u\left(u+4\right)

\mathrm{Factor\:out\:}-9\mathrm{\:from\:}-9u-36=-9\left(u+4\right)

u^2-5u-36=u\left(u+4\right)-9\left(u+4\right)

\mathrm{Factor\:out\:common\:term\:}u+4\\\left(u+4\right)\left(u-9\right)

u^2-5u-36=\left(u+4\right)\left(u-9\right)=0

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions to the quadratic equation are:

\:u=-4,\:u=9

Substitute back u=x^2, solve for x

x^4-5x^2-36=(u-9)(u+4)=(x^2-9)(x^2+4)

Apply the difference of squares formula

x^4-5x^2-36=(x^2-9)(x^2+4)=(x-3)(x+3)(x^2+4)

(x-3)(x+3)(x^2+4)=0

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions are:

\:x=3,\:x=-3,\:x=2i,\:x=-2i

Because two of the solutions are complex roots the only x-intercepts are x=3,\:x=-3

3 0
3 years ago
The sides of each square in the potholder measure 1in. What is the perimeter and area of the potholder?
Butoxors [25]
Perimeter=20 and the area=25
8 0
4 years ago
Read 2 more answers
Which of the following is the correct graph of the compound inequality 4p + 1 > −11 or 6p + 3 < 39?
adoni [48]

Answer:

D. Number line with shading everywhere

1. p>-3

2. p<6

Step-by-step explanation:

1. 4p+1>-11

<em>Subtract by 1 both sides of equation.</em>

<em>4p+1-1>-11+1</em>

<em>Simplify.</em>

<em>4p>-12</em>

<em>Divide by 4 from both sides of equation.</em>

<em>4p/4>-12/4</em>

<em>Simplify, to find the answer.</em>

<em>-12/4=-3</em>

<em>p>-3 is the correct answer.</em>

<em>____________________________</em>

<em>2. 6p+3<39</em>

<em>Subtract by 3 from both sides of equatoin.</em>

<em>6p+3-3<39-3</em>

<em>Simplify.</em>

<em>39-3=36</em>

<em>6p<36</em>

<em>Divide by 6 from both sides of equation.</em>

<em>6p/6<36/6</em>

<em>Simplify, to find the answer.</em>

<em>36/6=6</em>

<em>p<6 is the correct answer.</em>

<u><em>D is the correct answer.</em></u>

5 0
3 years ago
Read 2 more answers
Find a real number between each pair of numbers 4.14 and 29/7
chubhunter [2.5K]
One answer could be: 4.15
8 0
3 years ago
What is the answer to this problem <br> -4x+7y=26
sergiy2304 [10]
Do you want us to graph it for you or change it to stand which one?
8 0
2 years ago
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