Question

Find the vertex of the parabola y=2x^2-16x+34

Answer 1

Answer:

The standard equation is y=ax^2+bx+k and the vertex way is y=a(x-h)(x-h)+x

so the coordinate for x is -b/2a, for your problem a=-4   b=-16 so the coordinate for x is -(-16)/(2*(-4))=-2. Now you have to replace x=-2 in your equation y=-4(-2)^2-16(-2)-11= 5.

The vertex is (-2, 5)

Step-by-step explanation: