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3 years ago

Find the volume of the cone. Round your answer to the nearest tenth.

Mathematics

1 answer:

Alchen [17]3 years ago

6 0

Answer:

The volume of the cone is 16.8 in cubed.

Step-by-step explanation:

The formula for a cone is πr^2 multiplied by h/3. The r is radius and h is height. So throwing in the values for the variables we get 16.8 in cubed.

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HELP PLEASE <br> 5/12-(x-3)/6≤(x-2)/3<br> Solve with a step by step solution

zlopas [31]

Answer:x>3 1/6

Step-by-step explanation:

5/12-(x-3)/6 <(x-2)/3

5/12 *12-(x-3)/6*12<(x-2)/6*12

5-2(x-3)<4(x-2)

5-2x+6<4x-8

-2x+11<4x-8

-2x<4x-19

-6x<-19

-6x(-1)<-19(-1)

6x>19

x>19/6

x>3 1/6

just change all the inequality signs to a x is greater or equal to 3 1/6 and on the rest change to and < and equal sign only put > or equal sign on the last three lines

8 0

3 years ago

The midpoint of the coordinates (3, 15) and (20,8) is -

Nat2105 [25]

Answer:

The midpoint of the given coordinates is $(\frac{23}{2},\frac{23}{2})\ or\ (11.5,11.5)$ .

Step-by-step explanation:

We have given two coordinates (3,15) and (20,8).

Let we have given a line segment PQ whose P coordinate is (3,15) and Q coordinate is (20,8).

We have to find out the mid point M(x,y) of the line segment PQ.

Solution,

By the mid point formula of coordinates, which is;

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

On substituting the given values, we get;

$M(x,y)=(\frac{3+20}{2}, \frac{15+8}{2})\\\\M(x,y)=(\frac{23}{2},\frac{23}{2})$

We can also say that $M(x,y)=(11.5,11.5)$

Hence The midpoint of the given coordinates is $(\frac{23}{2},\frac{23}{2})\ or\ (11.5,11.5)$ .

3 0

3 years ago

Find measure angle AEB & EAD

wel

AEB will be 90 and
EAD will be 45

8 0

3 years ago

How to find the volume of a sheer

kupik [55]

the volume of a sphere can be calculated with the formula v=4/3(pi)(r)^3

6 0

3 years ago

I need to solve for a and b

Jlenok [28]

Answer:

Not sure Sorry i couldn't help

Step-by-step explanation:

5 0

3 years ago