You would probably have to measure it greatest distance by ur least distance and subtract or add
The equation for inflation is
A = P*(1+r)^t
which is an exponential growth equation (if r > 0). If r < 0, then we have deflation.
where...
A = final price after t years
P = initial starting price
r = rate of inflation in decimal form
t = number of years
In this case,
A = unknown (we're solving for this)
P = 280 is the starting price
r = 0.05 is the decimal form of 5%
t = 2 years
We will plug these three pieces of info into the formula to get...
A = P*(1+r)^t
A = 280*(1+0.05)^2
A = 280*(1.05)^2
A = 280*(1.1025)
A = 308.70
Answer: 308.70 dollars
Answer:
The first answer is 36 and the second is 80 because each pattern increases by one tile longer and wider so pattern 4 would be 4 by 4 so there would be 16 square tiles and 16 circular tiles and pattern 5 would have 25 square tiles and 20 circular tiles.
Answer:0.29
Step-by-step explanation:
An average of six cell phone thefts is reported in San Francisco per day. This means our mean value, u = 6
For poisson distribution,
P(x=r) = (e^-u×u^r)/r!
probability that four cell phones will be reported stolen tomorrow=
P(x=4)= (e^-6×6^4)/4!
= (0.00248×1296)/4×3×2×1
= 3.21408/24=
0.13392
P(x=5)= (e^-6×6^5)/5!
= (0.00248×7776)/5×4×3×2×1
= 19.28448/120
= 0.1607
probability that four or five cell phones will be reported stolen tomorrow
= P(x=4) + P(x=5)
= 0.13392 + 0.1607
= 0.294624
Approximately 0.29
A. Factor the numerator as a difference of squares:
c. As
, the contribution of the terms of degree less than 2 becomes negligible, which means we can write
e. Let's first rewrite the root terms with rational exponents:
![\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bx%5Cto1%7D%5Cfrac%7B%5Csqrt%5B3%5Dx-x%7D%7B%5Csqrt%20x-x%7D%3D%5Clim_%7Bx%5Cto1%7D%5Cfrac%7Bx%5E%7B1%2F3%7D-x%7D%7Bx%5E%7B1%2F2%7D-x%7D)
Next we rationalize the numerator and denominator. We do so by recalling
In particular,
so we have
For
and
, we can simplify the first term:
So our limit becomes
