At th x-intercept y=o
∴40x + 70 = 0
40x = -70
x = -70/40
x = -1.75
x intercepr = (-1.75,0)
It's already in the simplest form.
Vertex is now at (-1,5)
for
y=a(x-h)^2+k
vertex is (h,k)
so veertex is (-1,5)
y=a(x-(-1))^2+5
y=a(x+1)^2+5
a is a constant, we will asssume that it is 1 because all the choices have 1
y=1(x+1)^2+5
y=(x+1)^2+5
2nd option
Answer:
Center (6 , -5) and radius = 3
Step-by-step explanation:
The Standard equation of circle can be written as
(x - a)² + (y - b)² = r²
with center (a , b) and radius = r
Now from given circle equation
(x - 6)² + (y +5)² = 9
so, from here center of circle (6 , -5) and radius = 3
Answer:
See explanation
Step-by-step explanation:
Triangles ΔABC and ΔBAD are congruent. So,
- AB ≅ BA;
- AC ≅ BD;
- BC ≅ AD;
- ∠ABC ≅ ∠BAD;
- ∠BCA ≅ ∠ADB;
- ∠CAB ≅ ∠DBA.
Consider triangles AEC and BED. In these triangles,
- AC ≅ BD;
- ∠EAC ≅ ∠EBD (because ∠CBA ≅ ∠BAD);
- ∠AEC ≅ ∠BED (as vertical angles).
So, ΔAEC ≅ ΔBED. Thus,
AE ≅ EB.
This means that segment CD bisects segment AD.
