Answer:
Comprimento: 28.9 m; Largura: 11.1 m
Step-by-step explanation:
P = 2(C + L) = 80
A = CL = 320
2(C + L) = 80
CL = 320
C + L = 40
CL = 320
C = 40 - L
CL = 320
(40 - L)L = 320
40L - L^2 = 320
L^2 - 40L + 320 = 0
aL^2 + bL + c = 0
or
L = 28.9
C = 40 - L = 40 - 28.9 = 11.1
Answer: Comprimento: 28.9 m; Largura: 11.1 m
To find this we can do 2/6 divided by 1/9.
the answer will be 3.
Answer:
6/7 ≈ 85.7%
Step-by-step explanation:
The probability that a 0 was transmitted and received is 0.5·0.9 = 0.45.
The probability that a 1 was transmitted and a 0 received is 0.5·0.15 = 0.075.
Then the probability that a 0 was received is 0.45 +0.075 = 0.525.
The probability of interest is ...
p(0 transmitted | 0 received) = p(0 transmitted & received)/p(0 received)
= 0.45/0.525 = 6/7 ≈ 85.7%
Answer with Step-by-step explanation:
We are given that point B lies on the segment AC.
Length of AC= a cm
We have to find the the distance between the midpoint of segment AB and BC.
When B lies on the segment AC.
Let mid point of segment AB and BC are E and F.
E is the midpoint of segment AB.
Therefore,
Distance between E and F is given by
Hence, the distance between the midpoints of segment AB and BC is given by
XY = −1−(−10) = 9
(line x = −5) = −5−(−9) = 4
Area = 1/2 * 9 * 4 = 18